• JAVA实现两种方法反转单列表


    /**  
     * @author luochengcheng  
     * 定义一个单链表  
     */  
    class Node {   
        //变量   
        private int record;   
        //指向下一个对象   
        private Node nextNode;   
      
        public Node(int record) {   
            super();   
            this.record = record;   
        }   
        public int getRecord() {   
            return record;   
        }   
        public void setRecord(int record) {   
            this.record = record;   
        }   
        public Node getNextNode() {   
            return nextNode;   
        }   
        public void setNextNode(Node nextNode) {   
            this.nextNode = nextNode;   
        }   
    }   
      
    /**  
     * @author luochengcheng  
     *  两种方式实现单链表的反转(递归、普通)  
     *  新手强烈建议旁边拿着纸和笔跟着代码画图(便于理解)  
     */  
    public class ReverseSingleList {   
        /**   
         * 递归,在反转当前节点之前先反转后续节点   
         */  
        public static Node reverse(Node head) {   
            if (null == head || null == head.getNextNode()) {   
                return head;   
            }   
            Node reversedHead = reverse(head.getNextNode());   
            head.getNextNode().setNextNode(head);   
            head.setNextNode(null);   
            return reversedHead;   
        }   
      
        /**   
         * 遍历,将当前节点的下一个节点缓存后更改当前节点指针   
         *    
         */  
        public static Node reverse2(Node head) {   
            if (null == head) {   
                return head;   
            }   
            Node pre = head;   
            Node cur = head.getNextNode();   
            Node next;   
            while (null != cur) {   
                next = cur.getNextNode();   
                cur.setNextNode(pre);   
                pre = cur;   
                cur = next;   
            }   
            //将原链表的头节点的下一个节点置为null,再将反转后的头节点赋给head      
            head.setNextNode(null);   
            head = pre;   
               
            return head;   
        }   
      
        public static void main(String[] args) {   
            Node head = new Node(0);   
            Node tmp = null;   
            Node cur = null;   
            // 构造一个长度为10的链表,保存头节点对象head      
            for (int i = 1; i < 10; i++) {   
                tmp = new Node(i);   
                if (1 == i) {   
                    head.setNextNode(tmp);   
                } else {   
                    cur.setNextNode(tmp);   
                }   
                cur = tmp;   
            }   
            //打印反转前的链表   
            Node h = head;   
            while (null != h) {   
                System.out.print(h.getRecord() + " ");   
                h = h.getNextNode();   
            }   
            //调用反转方法   
            head = reverse2(head);   
            System.out.println("
    **************************");   
            //打印反转后的结果   
            while (null != head) {   
                System.out.print(head.getRecord() + " ");   
                head = head.getNextNode();   
            }   
        }   
    }  
  • 相关阅读:
    第四次寒假作业
    寒假作业三
    寒假作业二
    关于C语言
    寒假作业2代码
    计算机小白
    软工第二次作业
    新开始
    android 自定义滑动按钮
    新知识 HtMl 5
  • 原文地址:https://www.cnblogs.com/lvxiaowei/p/4314111.html
Copyright © 2020-2023  润新知