给定两个非空链表来表示两个非负整数。位数按照逆序方式存储,它们的每个节点只存储单个数字。将两数相加返回一个新的链表。
你可以假设除了数字 0 之外,这两个数字都不会以零开头。
示例:
输入:(2 -> 4 -> 3) + (5 -> 6 -> 4) 输出:7 -> 0 -> 8 原因:342 + 465 = 807
/** * Definition for singly-linked list. * public class ListNode { * public int val; * public ListNode next; * public ListNode(int x) { val = x; } * } */ public class Solution { public ListNode AddTwoNumbers(ListNode l1, ListNode l2) { ListNode n1 = l1; ListNode n2 = l2; ListNode res = new ListNode(0); ListNode p = res; int sum = 0; while(n1 != null || n2 != null){ if(n1 != null && n2 != null){ sum += n1.val + n2.val; n1 = n1.next; n2 = n2.next; } else if(n1 != null){ sum += n1.val; n1 = n1.next; } else if(n2 != null){ sum += n2.val; n2 = n2.next; } else { break; } if(sum < 10){ ListNode node = new ListNode(sum); p.next = node; p = node; sum = 0; } else{ ListNode node = new ListNode(sum-10); p.next = node; p = node; sum = 1; } } if(sum == 1){ ListNode node = new ListNode(1); p.next = node; p = node; } return res.next; } }