• BZOJ 3473: 字符串 (广义后缀自动机)


    /*
    广义后缀自动机, 每次加入维护 该right集合的set, 然后可以更新所有的parent,最终能够出现在k个串中right集合也就是set大小大于等于k的部分
    这样的话就给了我们要跳的节点加了一个限制, 也就是跳的时候调到第一个sz>= k的节点, 因为更长的话答案不会增加
    数据范围非常迷 
    
    好吧 暴力合并set复杂度过高 
    暴力更新祖先的情况竟然会少一个log 
    
    */
    
    #include<cstdio>
    #include<algorithm>
    #include<cstring>
    #include<queue>
    #include<set>
    #include<string> 
    #include<iostream>
    #define ll long long 
    #define mmp make_pair
    #define M 400020
    using namespace std;
    int read()
    {
    	int nm = 0, f = 1;
    	char c = getchar();
    	for(; !isdigit(c); c = getchar()) if(c == '-') f = -1;
    	for(; isdigit(c); c = getchar()) nm = nm * 10 + c - '0';
    	return nm * f;
    }
    int lst = 1, cnt = 1, fa[M], len[M], ch[M][26], tim[M], a[M], n, k;
    ll f[M], cor[M], g[M];
    //set<int> st[M];
    string s[M];
    //vector<int> to[M]; 
    void insert(int c)
    {
    	int p = ++cnt, f = lst;
    	lst = p;
    	len[p] = len[f] + 1;
    	while(f && !ch[f][c]) ch[f][c] = p, f = fa[f];
    	if(!f) fa[p] = 1;
    	else
    	{
    		int q = ch[f][c];
    		if(len[q] == len[f] + 1) fa[p] = q;
    		else
    		{ 
    			int nq = ++cnt;
    			memcpy(ch[nq], ch[q], sizeof(ch[nq]));
    			fa[nq] = fa[q];
    			len[nq] = len[f] + 1;
    			fa[p] = fa[q] = nq;
    			while(f && ch[f][c] == q) ch[f][c] = nq, f = fa[f];
    		}
    	}
    }
    
    //void dfs(int now)
    //{
    //	for(int i = 0; i < to[now].size(); i++)
    //	{
    //		int vj = to[now][i];
    //		dfs(vj);
    //		for(set<int>::iterator it = st[vj].begin(); it != st[vj].end(); it++)
    //		{
    //			st[now].insert(*it);
    //		}
    //	}
    //	f[now] = st[now].size();
    //}
    
    int main()
    {
    	ios::sync_with_stdio(false);
    	cin >> n >> k;
    	for(int i = 1; i <= n; i++)
    	{
    		cin >> s[i];
    		lst = 1;
    		int l = s[i].length();
    		for(int j = 0; j < l; j++)
    		{
    			insert(s[i][j] - 'a');
    		}
    	}
    	for(int i = 1; i <= n; i++)
    	{
    		int now = 1;
    		for(int j = 0; j < s[i].length(); j++)
    		{
    			int c = s[i][j] - 'a';
    			now = ch[now][c];
    			int p = now;
    			for(; p && cor[p] != i; p = fa[p]) g[p]++, cor[p] = i;
    		}
    	}
    	for(int i = 1; i <= cnt; i++) tim[len[i]]++;
    	for(int i = 1; i <= cnt; i++) tim[i] += tim[i - 1];
    	for(int i = 1; i <= cnt; i++) a[tim[len[i]]--] = i;
    //	for(int i = cnt; i >= 1; i--)
    //	{
    //		f[a[i]] = st[a[i]].size();
    //		for(set<int>::iterator it = st[a[i]].begin(); it != st[a[i]].end(); ++it)
    //		{
    //			st[fa[a[i]]].insert(*it);
    //		}
    //	}
    //	for(int i = 2; i <= cnt; i++) to[fa[i]].push_back(i);
    //	dfs(1); 
    	g[1] = 0;
    	for(int i = 1; i <= cnt; i++)
    	{
    		int now = a[i];
    		f[now] = f[fa[now]];
    		if(g[now] >= k) f[now] += len[now] - len[fa[now]];
    	}
    	if(k > n)
    	{
    		for(int i = 1; i <= n; i++) cout << "0 ";
    	}
    	else
    	{
    		ll ans;
    		for(int i = 1; i <= n; i++)
    		{
    			ans = 0;
    			int now = 1, l = s[i].length();
    			for(int j = 0; j < l; j++)
    			{
    				int c = s[i][j] - 'a';
    				now = ch[now][c];
    				ans += f[now];
    			}
    			cout << ans << " ";
    		}
    	}
    	return 0;
    }
    
    
    /*
    
    3 3
    
    abcdfdsadaseeeeeeeeefffffffffffffffffffffffffffffffffffffffffffeeeeeeee
    
    affsfdsdfewfeeeeeeffffffffeeeeeeeee
    
    abasdsadwdsadsadwdasdadafsafs
    
    */
    
    
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  • 原文地址:https://www.cnblogs.com/luoyibujue/p/10630135.html
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