/*
dp维护整体的概率, 每次相当于回退一格然后重新dp一格
*/
#include<cstdio>
#include<algorithm>
#include<iostream>
#include<cstring>
#include<queue>
#define ll long long
#define M 202
#define mmp make_pair
using namespace std;
int read()
{
int nm = 0, f = 1;
char c = getchar();
for(; !isdigit(c); c = getchar()) if(c == '-') f = -1;
for(; isdigit(c); c = getchar()) nm = nm * 10 + c - '0';
return nm * f;
}
const int mod = 1000000007;
int poww(int a, int b)
{
int ans = 1, tmp = a;
for(; b; b >>= 1, tmp = 1ll * tmp * tmp % mod) if(b & 1) ans = 1ll * ans * tmp % mod;
return ans;
}
void add(int &x, int y)
{
x += y;
x -= x >= mod ? mod : 0;
x += x < 0 ? mod : 0;
}
struct Note
{
int a, g, p;
bool operator < (const Note &b) const
{
return this->a < b.a;
}
}note[M][M], sta[M * M];
int m[M], q[M], n, v[M], tp;
int f[M], g[M], d[M], ans[M];
void work(int x)
{
if(x == 0)
{
for(int i = 0; i <= n; i++) g[i] = g[i + 1];
return;
}
int y = (1 + mod - x), invx = poww(x, mod - 2);
memset(d, 0, sizeof(d));
for(int i = 0; i <= n; i++)
{
d[i] = 1ll * g[i] * invx % mod;
add(g[i + 1], -1ll * d[i] * y % mod);
}
for(int i = 0; i <= n; i++) g[i] = d[i];
}
int main()
{
n = read();
int inv = poww(100 ,mod - 2);
for(int i = 1; i <= n; i++)
{
m[i] = read();
for(int j = 1; j <= m[i]; j++)
{
note[i][j].a = read(), note[i][j].g = 1ll * (100 - read()) * inv % mod, note[i][j].p = read();
add(q[i], note[i][j].p);
sta[++tp] = (Note) {note[i][j].a, i, j};
}
int inv = poww(q[i], mod - 2);
for(int j = 1; j <= m[i]; j++) note[i][j].p = 1ll * note[i][j].p * inv % mod;
}
sort(sta + 1, sta + tp + 1);
for(int i = 1; i <= n; i++) v[i] = read();
g[n] = 1;
for(int now = 1; now <= tp; now++)
{
int i = sta[now].g, j = sta[now].p;
work(f[i]);
for(int a = 0; a <= n; a++) add(ans[i], 1ll * note[i][j].p * v[a + 1] % mod * g[a] % mod * note[i][j].g % mod);
add(f[i], note[i][j].p);
for(int a = n; a >= 0; a--)
{
g[a] = 1ll * g[a] * f[i] % mod;
if(a) add(g[a], 1ll * (1 + mod - f[i]) * g[a - 1] % mod);
}
}
for(int i = 1; i <= n; i++) cout << ans[i] << "
";
return 0;
}