关于从request对象中获取路径的问题

从request对象中获取路径的问题：例如： 项目名为：tmall_web     请求的servlet名为：loginServlet

示例代码如下：

@Override
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        logger.info("========== LoginServlet ===============");
        PrintWriter out = response.getWriter();
        response.setContentType("text/html;charset=utf-8");

        out.print("***************************************");
        out.print("项目名：tmall_web ||  servlet名：loginServlet");
        out.print("***************************************");

        //获取的是项目名称:    /tmall_web
        String path = request.getContextPath();
        //获取项目请求根路径:   http://localhost:8080/tmall_web/
        String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
        //获得客户端的ip地址:   0:0:0:0:0:0:0:1
        String remoteAddress=request.getRemoteAddr();
        //获取servlet的请求路径： /loginServlet
        String servletPath=request.getServletPath();
        //获取项目的真实根目录，硬盘的位置:  D:911linpeng_work	mall_webweb
        //假如部署tomcat：获取到的是项目在tomcat的根路径：例如：C:UsersAdministratorDesktopapache-tomcat-8.5.20webappsROOT
        String realPath=request.getRealPath("/");
        //获取到用户名：null
        String remoteUser=request.getRemoteUser();
        //获取项目的资源目录: /tmall_web/loginServlet
        String requestURI=request.getRequestURI();
        //获取浏览器的请求url:   localhost:8080/tmall_web/loginServlet
        String requestURL=request.getRequestURL().toString();

        out.println("path:"+path+"<br>");
        out.println("basePath:"+basePath+"<br>");
        out.println("remoteAddr:"+remoteAddress+"<br>");
        out.println("servletPath:"+servletPath+"<br>");
        out.println("realPath:"+realPath+"<br>");
        out.println("remoteUser:"+remoteUser+"<br>");
        out.println("requestURI:"+requestURI+"<br>");
        out.println("requestURI:"+requestURL+"<br>");
    }

 以上为个人总结，如有错误的地方，望大家指正，谢谢！