• HTML5 FormData实现文件上传实例


    转载:https://www.cnblogs.com/hutuzhu/p/4409292.html

    表单提交,文件上传是一个常用又十分麻烦的功能,以前要上传文件通常都是借助插件或者flash来实现,噼里啪啦的加载一大堆东西。自从有了HTML5的FormData后,老板再也不用担心我的上传了。

    FormData可以把它理解成一个虚拟的表单对象,它只有一个方法append,这个可以在浏览器console一下就知道了。我们可以通过append向FormData里面添加各种需要提交的数据。

    你可以先创建一个空的 FormData 对象,然后使用 append() 方法向该对象里添加字段,如下:var oMyForm = new FormData();

    oMyForm.append("username", "Groucho");
    oMyForm.append("accountnum", 123456); // 数字123456被立即转换成字符串"123456"
     
    // fileInputElement中已经包含了用户所选择的文件
    oMyForm.append("userfile", fileInputElement.files[0]);var oReq = new XMLHttpRequest();
    oReq.open("POST", "http://foo.com/submitform.php");
    oReq.send(oMyForm);

    如果已经有一个Form表单,只需要把这个 form 元素作为参数传入 FormData 构造函数即可:

    var newFormData = new FormData(someFormElement);
    var formElement = document.getElementById("myFormElement");
    var oReq = new XMLHttpRequest();
    oReq.open("POST", "submitform.php");
    oReq.send(new FormData(formElement));

    你还可以在已有表单数据的基础上,继续添加新的键值对,如下:

    var formElement = document.getElementById("myFormElement");
    formData = new FormData(formElement);
    formData.append("serialnumber", serialNumber++);
    oReq.send(formData);
    <form enctype="multipart/form-data" method="post" name="fileinfo">
      <label>Your email address:</label>
      <input type="email" autocomplete="on" autofocus name="userid" placeholder="email" required size="32" maxlength="64" /><br />
      <label>Custom file label:</label>
      <input type="text" name="filelabel" size="12" maxlength="32" /><br />
      <label>File to stash:</label>
      <input type="file" name="file" required />
    </form>
    <div id="output"></div>
    <a href="javascript:sendForm()">Stash the file!</a>

    然后你就可以使用下面的代码来异步的上传用户所选择的文件:

    function sendForm() {
      var oOutput = document.getElementById("output");
      var oData = new FormData(document.forms.namedItem("fileinfo"));
     
      oData.append("CustomField", "This is some extra data");
     
      var oReq = new XMLHttpRequest();
      oReq.open("POST", "stash.php", true);
      oReq.onload = function(oEvent) {
        if (oReq.status == 200) {
          oOutput.innerHTML = "Uploaded!";
        } else {
          oOutput.innerHTML = "Error " + oReq.status + " occurred uploading your file.<br />";
        }
      };
     
      oReq.send(oData);
    }

    你还可以使用 jQuery 来发送 FormData,但必须要正确的设置相关选项:

    var fd = new FormData(document.getElementById("fileinfo"));
    fd.append("CustomField", "This is some extra data");
    $.ajax({
      url: "stash.php",
      type: "POST",
      data: fd,
      processData: false,  // 告诉jQuery不要去处理发送的数据
      contentType: false   // 告诉jQuery不要去设置Content-Type请求头
    });

    一个完整的例子:

    <!DOCTYPE html>
    <html lang="en">
    <head>
        <meta charset="UTF-8">
        <title>FormData</title>
    </head>
    <body>
        <form name="form1" id="form1">  
            <p>name:<input type="text" name="name" ></p>  
            <p>gender:<input type="radio" name="gender" value="1">male <input type="radio" name="gender" value="2">female</p>  
            <p>photo:<input type="file" name="photo" id="photo"></p>  
            <p><input type="button" name="b1" value="submit" onclick="fsubmit()"></p>  
        </form>  
        <div id="result"></div>
    </script>
        <script type="text/javascript">
            function fsubmit() {
                var form=document.getElementById("form1");
                var formData=new FormData(form);
                var oReq = new XMLHttpRequest();
                oReq.onreadystatechange=function(){
                  if(oReq.readyState==4){
                    if(oReq.status==200){
                        var json=JSON.parse(oReq.responseText);
                        var result = '';
                        // result += 'name=' + ret['name'] + '<br>';
                        // result += 'gender=' + ret['gender'] + '<br>';
                         result += '<img src="' + json['photo'] + '" width="100">';
                         $('#result').html(result);
                    }
                  }
                }
                oReq.open("POST", "server.php");
                oReq.send(formData); 
                return false;
            } 
        </script>
    </body>
    </html>
    View Code

    server.php文件:

    <?php  
    $name = isset($_POST['name'])? $_POST['name'] : '';  
    $gender = isset($_POST['gender'])? $_POST['gender'] : '';  
    $filename = time().substr($_FILES['photo']['name'], strrpos($_FILES['photo']['name'],'.'));  
    $response = array();  
    if(move_uploaded_file($_FILES['photo']['tmp_name'], $filename)){  
        $response['isSuccess'] = true;  
        $response['name'] = $name;  
        $response['gender'] = $gender;  
        $response['photo'] = $filename;  
    }else{  
        $response['isSuccess'] = false;  
    }  
    echo json_encode($response);  
    ?>
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  • 原文地址:https://www.cnblogs.com/lst619247/p/11014774.html
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