• 实验一


    实验一  命令解释程序的编写

    一、目的和要求

    1. 实验目的

    (1)掌握命令解释程序的原理;

    (2)掌握简单的DOS调用方法;

    (3)掌握C语言编程初步。

    2.实验要求

    编写类似于DOS,UNIX的命令行解释程序

    (1)自行定义系统提示符

    (2)自定义命令集(8-10个)

    (3)用户输入HELP以查找命令的帮助

    (4)列出命令的功能,区分内部还是外部命令

    (5)用户输入QUIT退出

    (6)内部命令有dir, cd, md, rd, cls, date, time, ren, copy等。

    二、实验内容

    根据教师指定的实验课题,完成设计、编码、测试工作。

    、实验环境

    1.PC微机

    2.Windows 操作系统

    3.C/C++程序开发集成环境

    四、实验原理及核心算法参考程序段

    显示程序提示信息;

    While(1)

    { 显示提示符;

    接收键盘的字符串;

    判断是否quit程序退出指令,是则退出;

    判断是否内部命令,并给出相应的信息,否则给出错误信息;

    显示退出程序信息;

    实验内容:

    #include<stdio.h>
    #include<string.h>
    void main()
    {
    char*b[1]={"dir","cd","md","rd","cls","date","time","ren","copy","help","quit"};
    int pan(char ch1[],char*j[11];
    char a[10],*p=a;
    printf("Welcome\nPlease enter a command!\nEnter 'quit' to quit\nFor help,Enter'help'\n");
    c1: printf("c:\>$");
    scanf("%s",a);
    pan(p,b);
    if(strcmp(a,b[10]!=0)
    goto c1;
    else printf("out of work!\n");
    }
    int pan ch1[],char*j[11])
    {
    int i;
    for(i=0;i<=11;i++)
    if(strcmp(ch 1,j[i]==0)
    {
    switch(i)
    {
    case 0:printf("Command name is dir.\nIt's function is list file.\nIt's an internal command.\nVolume in drive K gas no labe.\nVolume Serial Number is 60F0-6C24n\n");break;
    case 1:printf("Command name is cd.t's function is list file.\nIt's an internal command.\nVolume in drive K gas no labe.\nVolume Serial Number is 60F0-6C24n\n");break;
    case 2:printf("Command name is md.\nIt's function is list file.\nIt's an internal command.\nVolume in drive K gas no labe.\nVolume Serial Number is 60F0-6C24n\n");break;
    case 3printf("Command name is rd.\nIt's function is list file.\nIt's an internal command.\nVolume in drive K gas no labe.\nVolume Serial Number is 60F0-6C24n\n");break;
    case 4:printf("Command name is cls.\nIt's function is list file.\nIt's an internal command.\nVolume in drive K gas no labe.\nVolume Serial Number is 60F0-6C24n\n");break;
    case 5:printf("Command name is date.\nIt's function is list file.\nIt's an internal command.\nVolume in drive K gas no labe.\nVolume Serial Number is 60F0-6C24n\n");break;
    case 6:printf("Command name is time.\nIt's function is list file.\nIt's an internal command.\nVolume in drive K gas no labe.\nVolume Serial Number is 60F0-6C24n\n");break;
    case 7:printf("Command name is ren.\nIt's function is list file.\nIt's an internal command.\nVolume in drive K gas no labe.\nVolume Serial Number is 60F0-6C24n\n");break;
    case 8:printf("Command name is copy.\nIt's function is list file.\nIt's an internal command.\nVolume in drive K gas no labe.\nVolume Serial Number is 60F0-6C24n\n");break;
    case 9:printf("dir\tcd\tmd\tcls\ndate\ttime\tren\tcopy\nEnter\"quite\"to quit this program!!\n");break;
    case 10:printf("Thanks for using it ,bye!!\n");break;
    return 1;
    }
    printf("No this one!!\nNot a internal commal.\n");
    return 0;
    }

     感想:c语言虽然之前学过,可是都忘得七七八八了,虽然代码大多数为参考网络的,但也有理解了。通过这次的实验,认识到了代码编程不仅仅只是懂了就好,还得多多练习。

  • 相关阅读:
    es6类
    ES6模块化
    es6之常/变量
    es6之结构赋值
    es6之箭头函数、rest函数
    es6的新方法
    数组的使用方法
    Vue接口调用问题
    监听器和计算属性
    Vue路由
  • 原文地址:https://www.cnblogs.com/lsq21/p/4394417.html
Copyright © 2020-2023  润新知