Description
A fractal is an object or quantity that displays self-similarity, in a somewhat technical sense, on all scales. The object need not
exhibit exactly the same structure at all scales, but the same "type" of structures must appear on all scales.
A box fractal is defined as below :
A box fractal of degree 1 is simply
X
A box fractal of degree 2 is
X X
X
X X
If using B(n - 1) to represent the box fractal of degree n - 1, then a box fractal of degree n is defined recursively as following
B(n - 1) B(n - 1)
B(n - 1)
B(n - 1) B(n - 1)
Your task is to draw a box fractal of degree n.
Input
The input consists of several test cases. Each line of the input contains a positive integer n which is no greater than 7.
The last line of input is a negative integer −1 indicating the end of input.
Output
For each test case, output the box fractal using the 'X' notation. Please notice that 'X' is an uppercase letter. Print a line
with only a single dash after each test case.
Sample Input
1
2
3
4
-1
Examples
Input
3
2 3 2
2
3 2
2 3
Output
X
-
X X
X
X X
-
X X X X
X X
X X X X
X X
X
X X
X X X X
X X
X X X X
-
X X X X X X X X
X X X X
X X X X X X X X
X X X X
X X
X X X X
X X X X X X X X
X X X X
X X X X X X X X
X X X X
X X
X X X X
X X
X
X X
X X X X
X X
X X X X
X X X X X X X X
X X X X
X X X X X X X X
X X X X
X X
X X X X
X X X X X X X X
X X X X
X X X X X X X X
-
Analysis
一句话题意：打印图形
其实就是把删一个图形在右上、左下、右下分别复制粘贴一遍就OK了
然而我居然习惯输出空格导致WA了3发。。。
代码
真的很水啦。。。
#include<iostream>
#include<algorithm>
#include<cstdlib>
#include<cstdio>
#include<cstring>
using namespace std;
int n,cnt[100];
char co[1000][1000];
void copy(int k,int x,int y){
for(int j=1;j<=cnt[k-1];j++){
for(int l=cnt[k-1]*2+1;l<=cnt[k];l++){//右上
co[j][l]=co[j][l-cnt[k-1]*2];
}
}
for(int j=cnt[k-1]+1;j<=cnt[k-1]*2;j++){//中间
for(int l=cnt[k-1]+1;l<=cnt[k-1]*2;l++){
co[j][l]=co[j-cnt[k-1]][l-cnt[k-1]];
}
}
for(int j=cnt[k-1]*2+1;j<=cnt[k];j++){//左下
for(int l=1;l<=cnt[k-1];l++){
co[j][l]=co[j-cnt[k-1]*2][l];
}
}
for(int j=cnt[k-1]*2+1;j<=cnt[k];j++){//右下
for(int l=cnt[k-1]*2+1;l<=cnt[k];l++){
co[j][l]=co[j-cnt[k-1]*2][l-cnt[k-1]*2];
}
}
}
int main(){
cnt[0]=cnt[1]=1;
for(int i=2;i<=10;i++)cnt[i]=cnt[i-1]*3;
while(cin>>n){
memset(co,' ',sizeof(co));
if(n==-1)return 0;
co[1][1]='X';
for(int i=2;i<=n;i++){
copy(i,cnt[i],cnt[i]);
}
for(int i=1;i<=cnt[n];i++){
for(int j=1;j<=cnt[n];j++){
cout<<co[i][j];
}
cout<<endl;
}
cout<<"-"<<endl;
}
}