• P2564 [SCOI2009]生日礼物


    题意

    • 寻找最小的区间使得它包含全部的(k)个元素

    (set)存下每个颜色最后的出现点,直接求出最大值即可

    #include<bits/stdc++.h>
    #define For(i, a, b) for(int i = (a), en = (b); i <= en; ++i)
    #define Rof(i, a, b) for(int i = (a), en = (b); i >= en; --i)
    #define Tra(u, i) for(int i = hd[u]; ~i; i = e[i].net)
    #define cst const
    #define LL long long
    #define DD double
    #define LD long double
    #define pb push_back
    #define mp make_pair
    #define fir first
    #define sec second
    #define inf 0x3f3f3f3f
    #define Inf 0x3f3f3f3f3f3f3f3f
    #define eps 1e-12
    #define maxn 1000000
    using namespace std;
    
    int n, k, b[maxn + 5], cnt = 0, as = inf;
    vector<int> vec[maxn + 5], T[maxn + 5];
    
    template <class T>
    void read(T &x){
    	char ch;
    	bool ok;
    	for(ok = 0, ch = getchar(); !isdigit(ch); ch = getchar()) if(ch == '-') ok = 1;
    	for(x = 0; isdigit(ch); x = x * 10 + ch - '0', ch = getchar());
    	if(ok) x = -x;
    }
    
    int find(int x){return lower_bound(b + 1, b + cnt + 1, x) - b;}
    
    int to[maxn + 5];
    set<pair<int, int> > se;
    int main(){
    	//freopen("gift.in", "r", stdin);
    	//freopen("gift.out", "w", stdout);
    	read(n); read(k);
    	For(i, 1, k){
    		int t; read(t);
    		For(j, 1, t){
    			int x; read(x);
    			T[i].pb(x);
    			b[++cnt] = x;
    		}
    	}
    	sort(b + 1, b + cnt + 1);
    	cnt = unique(b + 1, b + cnt + 1) - b - 1;
    	For(i, 1, k) for(auto j : T[i]) vec[find(j)].pb(i);
    	For(i, 1, cnt){
    		for(auto j : vec[i]){
    			se.erase(mp(to[j], j));
    			se.insert(mp(to[j] = i, j));
    		}
    		if(se.size() == k) as = min(as, b[i] - b[se.begin()->fir]);
    	}
    	printf("%d
    ", as);
    	return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/lprdsb/p/13922476.html
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