• 1129 Recommendation System


    1129 Recommendation System (25 分)

    Recommendation system predicts the preference that a user would give to an item. Now you are asked to program a very simple recommendation system that rates the user's preference by the number of times that an item has been accessed by this user.

    Input Specification:

    Each input file contains one test case. For each test case, the first line contains two positive integers: N (≤ 50,000), the total number of queries, and K (≤ 10), the maximum number of recommendations the system must show to the user. Then given in the second line are the indices of items that the user is accessing -- for the sake of simplicity, all the items are indexed from 1 to N. All the numbers in a line are separated by a space.

    Output Specification:

    For each case, process the queries one by one. Output the recommendations for each query in a line in the format:

    where query is the item that the user is accessing, and rec[i] (i=1, ... K) is the i-th item that the system recommends to the user. The first K items that have been accessed most frequently are supposed to be recommended in non-increasing order of their frequencies. If there is a tie, the items will be ordered by their indices in increasing order.

    Note: there is no output for the first item since it is impossible to give any recommendation at the time. It is guaranteed to have the output for at least one query.

    知识点:STL的使用,排序

    思路:每一次输入后,都要让所有元素有序。如果利用线性结构,那么他的时间复杂度是O(n),在数据量大的时候也是不行的。利用STL的set,插入的时间复杂度降为O(logN)

     1 #include <cstdio>
     2 #include <set>
     3 using namespace std;
     4 const int maxn = 500050;
     5 
     6 int clickTime[maxn];
     7 struct nodetype{
     8     int v,cnt;
     9     nodetype(int a,int b) : v(a), cnt(b) {}
    10     bool operator < (const nodetype &a) const    {
    11         return (cnt!=a.cnt)?cnt>a.cnt:v<a.v;
    12     }    
    13 };
    14 
    15 int main(int argc, char *argv[]) {
    16     fill(clickTime,clickTime+maxn,0);
    17     
    18     int n,k,tmp;
    19     scanf("%d %d",&n,&k);
    20     set<nodetype> s;
    21     for(int i=1;i<=n;i++){
    22         scanf("%d",&tmp);
    23         if(i!=1){
    24             printf("%d:",tmp);
    25             int cnt=0;
    26             for(auto it=s.begin();cnt<k&&it!=s.end();it++){
    27                 printf(" %d",it->v);
    28                 cnt++;
    29             }
    30             printf("
    ");
    31         }
    32         
    33         auto it = s.find(nodetype(tmp,clickTime[tmp]));
    34         if(it!=s.end()){
    35             s.erase(nodetype(tmp,clickTime[tmp]));
    36         }
    37         s.insert(nodetype(tmp,clickTime[tmp]+1));
    38         clickTime[tmp]++;
    39     }
    40 }
  • 相关阅读:
    自动补全的java封装
    angular创建服务
    forEach和for包含异步调用的区别
    angular获取dom节点
    angular父组件给子组件传值
    angular环境
    SQL Server DBA 30问 【itpub】 天高地厚
    【转】任务管理器各参数说明 天高地厚
    开机引导 天高地厚
    测试发现数据库性能问题后的SQL调优 天高地厚
  • 原文地址:https://www.cnblogs.com/lokwongho/p/9908526.html
Copyright © 2020-2023  润新知