从小到大排个序,然后能选就选
#include<iostream>
#include<cstdio>
#include<algorithm>
using namespace std;
const int N=50005;
int n,m,d,l,ans,a[N];
int read()
{
int r=0,f=1;
char p=getchar();
while(p>'9'||p<'0')
{
if(p=='-')
f=-1;
p=getchar();
}
while(p>='0'&&p<='9')
{
r=r*10+p-48;
p=getchar();
}
return r*f;
}
int main()
{
n=read(),m=read(),d=read(),l=read();
for(int i=1;i<=n;i++)
a[i]=read();
sort(a+1,a+n+1);
for(int i=1;i<=n;i++)
if(a[i]-ans/m*d>=l)
ans++;
printf("%d
",ans);
return 0;
}