Can you solve this equation?
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 5413 Accepted Submission(s): 2568
Problem Description
Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.
Now please try your lucky.
Input
The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);
Output
For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.
Sample Input
2
100
-4
Sample Output
1.6152
No solution!
二分入门题
#include<stdio.h> #include<math.h> double y; double solve(double x) { double n; n=8*x*x*x*x + 7*x*x*x + 2*x*x + 3*x + 6; return n; } int main() { int t; double y,l,r,p,mid; scanf("%d",&t); while(t--) { scanf("%lf",&y); if(solve(0)>y||solve(100)<y) { printf("No solution! "); continue; } l=0.0,r=100.0; while(r-l>1e-9) { mid=(r+l)/2; p=solve(mid); if(p<y) l=mid; else r=mid; } printf("%.4lf ",mid); } return 0; }