一、首先,汉诺塔问题说简单不简单,说容易不容易,所以就是难,,,,(孩子欠揍)
下面是我给大家提供的源代码,仅供参考。
import turtle
class Stack:
def __init__(self):
self.items = []
def isEmpty(self):
return len(self.items) == 0
def push(self, item):
self.items.append(item)
def pop(self):
return self.items.pop()
def peek(self):
if not self.isEmpty():
return self.items[len(self.items) - 1]
def size(self):
return len(self.items)
def drawpole_3():#画出汉诺塔的poles
t = turtle.Turtle()
t.hideturtle()
def drawpole_1(k):
t.up()
t.pensize(10)
t.speed(100)
t.goto(400*(k-1), 100)
t.down()
t.goto(400*(k-1), -100)
t.goto(400*(k-1)-20, -100)
t.goto(400*(k-1)+20, -100)
drawpole_1(0)#画出汉诺塔的poles[0]
drawpole_1(1)#画出汉诺塔的poles[1]
drawpole_1(2)#画出汉诺塔的poles[2]
def creat_plates(n):#制造n个盘子
plates=[turtle.Turtle() for i in range(n)]
for i in range(n):
plates[i].up()
plates[i].hideturtle()
plates[i].shape("square")
plates[i].shapesize(1,8-i)
plates[i].goto(-400,-90+20*i)
plates[i].showturtle()
return plates
def pole_stack():#制造poles的栈
poles=[Stack() for i in range(3)]
return poles
def moveDisk(plates,poles,fp,tp):#把poles[fp]顶端的盘子plates[mov]从poles[fp]移到poles[tp]
mov=poles[fp].peek()
plates[mov].goto((fp-1)*400,150)
plates[mov].goto((tp-1)*400,150)
l=poles[tp].size()#确定移动到底部的高度(恰好放在原来最上面的盘子上面)
plates[mov].goto((tp-1)*400,-90+20*l)
def moveTower(plates,poles,height,fromPole, toPole, withPole):#递归放盘子
if height >= 1:
moveTower(plates,poles,height-1,fromPole,withPole,toPole)
moveDisk(plates,poles,fromPole,toPole)
poles[toPole].push(poles[fromPole].pop())
moveTower(plates,poles,height-1,withPole,toPole,fromPole)
myscreen=turtle.Screen()
drawpole_3()
n=int(input("请输入汉诺塔的层数并回车:
"))
plates=creat_plates(n)
poles=pole_stack()
for i in range(n):
poles[0].push(i)
moveTower(plates,poles,n,0,2,1)
myscreen.exitonclick()
把代码复制好,在python 3.7.2 Shell上运行,如图
可以看到效果,如图
这样汉诺塔问题就基本解决了,欢迎大家来评论-_- -_- -_-