• python-day9-集合数据类型


    pythons=['alex','egon','yuanhao','wupeiqi','gangdan','biubiu']
    linuxs=['wupeiqi','oldboy','gangdan']


    #求二者共同的部分:求即报名python又报名linux的学生
    # l=[]
    # for item in pythons:
    # if item in linuxs:
    # l.append(item)
    # print(l)


    #求只报名python,没有报名linux的学生
    # l=[]
    # for item in pythons:
    # if item not in linuxs:
    # l.append(item)
    # print(l)







    # 知识点回顾
    # 可变类型是不可hash类型
    # 不可变类型是可hash类型
    # d={[1,2,3]:'egon',}



    #定义集合
    #集合:可以包含多个元素,用逗号分割,
    #集合的元素遵循三个原则:
    #1:每个元素必须是不可变类型
    #2:没有重复的元素
    #3:无序
    # s={1,2,2,'eaaa',(1,2,3)} #s=set({1, 2, (1, 2, 3), 'eaaa'})
    # print(s,type(s))


    #优先掌握

    #  in 和 not in #成员检测操作符
    # pythons={'alex','egon','yuanhao','wupeiqi','gangdan','biubiu'}
    #
    # print('egon' in pythons)


    #
    #     |并集:老男孩所以报名的学生名字集合
    pythons={'alex','egon','yuanhao','wupeiqi','gangdan','biubiu'}
    linuxs={'wupeiqi','oldboy','gangdan'}

    #
    # s=pythons | linuxs
    # print(s)

    # print(pythons.union(linuxs))


    #     &交集:求二者共同的部分:求即报名python又报名linux的学生
    # pythons={'alex','egon','yuanhao','wupeiqi','gangdan','biubiu'}
    # linuxs={'wupeiqi','oldboy','gangdan'}
    # #
    # s=pythons & linuxs
    # print(s)
    #
    # print(pythons.intersection(linuxs))
    # print(linuxs.intersection(pythons))

    #
    #     -差集:求只报名python,没有报名linux的学生
    # pythons={'alex','egon','yuanhao','wupeiqi','gangdan','biubiu'}
    # linuxs={'wupeiqi','oldboy','gangdan'}
    # print(pythons - linuxs)
    # print(pythons.difference(linuxs))
    #
    # print(linuxs - pythons)
    # print(linuxs.difference(pythons))
    # #


    #     ^对称差集: 没有同时报名python和linux课程的学生名字集合
    # pythons={'alex','egon','yuanhao','wupeiqi','gangdan','biubiu'}
    # linuxs={'wupeiqi','oldboy','gangdan'}
    # print(pythons ^ linuxs)
    #
    # print(pythons.symmetric_difference(linuxs))
    # print(linuxs.symmetric_difference(pythons))





    #     ==
    set1={1,2,3}
    set2={1,2,3}

    # print(set1 == set2)

    #     >,>= ,<,<= 父集,子集

    set1={1,2,3,4,5}
    set2={1,2,3,4}
    # print(set1 >= set2)
    # print(set1.issuperset(set2))
    #
    # print(set2 <= set1)
    # print(set2.issubset(set1))


    #掌握
    linuxs={'wupeiqi','oldboy','gangdan'}
    # linuxs.add('asb') #set类型的集合是可变类型
    # linuxs.add([1,2,3]) #报错,只能添加不可变类型
    # print(linuxs)

    # res=linuxs.pop() #不用指定参数,随机删除,并且会有返回值
    # print(res)

    # res=linuxs.remove('oldboy') #指定元素删除,元素不存在则报错,单纯的删除,没有返回值,
    # # print(linuxs)
    # print(res)
    #
    # res= linuxs.discard('oldboy1111111') #指定元素删除,元素不存在不报错,单纯的删除,没有返回值,
    # # print(linuxs)
    # print(res)

    #了解
    linuxs={'wupeiqi','oldboy','gangdan'}
    new_set={'wupeiqi','alex_SB'}
    # linuxs.update(new_set)
    # print(linuxs)

    # new_set.update(linuxs)
    # print(new_set)


    # linuxs.clear()
    # linuxs.copy()


    set1={1,2,3}
    set2={4,1,2}
    # print(set1 - set2)
    # print(set1.difference(set2))

    # set1=set1-set2
    # print(set1)

    # set1=set1.difference(set2)
    # print(set1)

    # set1.difference_update(set2)
    # print(set1)



    # msg='hello'
    # msg=[1,2,'egon','egon']
    # msg=[1,2,'egon','egon',[1,2],[1,2]]
    # s=set(msg) #{1,2,'egon','egon',[1,2],[1,2]}
    # print(s)














    #for
    # pythons={'alex','egon','yuanhao','wupeiqi','gangdan','biubiu'}
    # for item in pythons:
    # print(item)
    #解压
    #
    # a,*_={'alex','egon','yuanhao','wupeiqi','gangdan','biubiu'}
    # print(a)

    #in:字符串,列表,元组,字典,集合
    #for:字符串,列表,元组,字典,集合
    #解压:字符串,列表,元组,字典,集合
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  • 原文地址:https://www.cnblogs.com/liuwei0824/p/7217806.html
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