• JSP第一周作业


    1.求1-100之间的偶数和?

    <%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
    <%
        String path = request.getContextPath();
        String basePath = request.getScheme() + "://"
                + request.getServerName() + ":" + request.getServerPort()
                + path + "/";
    %>
    
    <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
    <html>
    <head>
    <base href="<%=basePath%>">
    
    <title>My JSP 'index.jsp' starting page</title>
    <meta http-equiv="pragma" content="no-cache">
    <meta http-equiv="cache-control" content="no-cache">
    <meta http-equiv="expires" content="0">
    <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
    <meta http-equiv="description" content="This is my page">
    <!--
        <link rel="stylesheet" type="text/css" href="styles.css">
        -->
    </head>
    
    <body>
        求1-100的偶数和?
        <hr>
        <br>
    </body>
    
    <%
        int a, sum = 0;
        for (a = 1; a <= 100; a++) {
            if (a % 2 == 0) {
                sum += a;
            }
        }
    %>
    
    1-100中间的偶数和是:
    <%=sum%>
    </html>

     

     2.求1-100之间的素数之和=?

    <%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
    <%
        String path = request.getContextPath();
        String basePath = request.getScheme() + "://"
                + request.getServerName() + ":" + request.getServerPort()
                + path + "/";
    %>
    
    <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
    <html>
    <head>
    <base href="<%=basePath%>">
    
    <title>My JSP 'index.jsp' starting page</title>
    <meta http-equiv="pragma" content="no-cache">
    <meta http-equiv="cache-control" content="no-cache">
    <meta http-equiv="expires" content="0">
    <meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
    <meta http-equiv="description" content="This is my page">
    <!--
        <link rel="stylesheet" type="text/css" href="styles.css">
        -->
    </head>
    
    <body>
        求1-100的素数和?
        <hr>
        <br>
    </body>
    
    <%
        int i, j, sum = 0;
        for (i = 1; i <= 100; i++) {
            for (j = 2; j < i; j++) {
                if (i % j == 0) {
                    break;
                }
            }
            if (j == i) {
                sum += i;
            }
        }
    %>
    1-100中间的素数和是:
    <%=sum%>
    </html>

     

  • 相关阅读:
    use tomcat to access the file cross the environment
    data audit on hadoop fs
    Good practice release jar to Nexus
    套路!从Ruby 到 Cocoapods的发布
    单元测试之NSNull 检测
    UIwebView 和 H5交互详情
    IT 需要知道的一些专业名词和解释 (长期更新)
    Git 操作 学习资源 网址
    GCD
    软件工程——个人总结
  • 原文地址:https://www.cnblogs.com/liujiayi123/p/14475584.html
Copyright © 2020-2023  润新知