码死了...考试的时候基本上是写一会儿思考一会儿人生....考完了调了调...最后400行+....不应该这么长的....以后重写一下再补题解.....
也许这就是蒟蒻吧.jpg
安利cstdio博客翻译的题解.
#include<cstdio>
#include<cstring>
#include<cmath>
#include<set>
using namespace std;
const int mod=1000000007;
int X,Y,K;
int ax,ay,bx,by;
int xx[20],yy[20];
set<pair<int,int> > dict;
double direc(int a,int b){
if(a!=0)return double(b)/a;
else return 1e8;
}
int check1(int a,int b){
if(X==0&&Y==0)return -1;
int step1,step2;
if(a==0){
if(X==0){
double tmp=Y/(double)(b);
if(tmp>0&&(fabs(tmp-floor(tmp))<1e-8)){
step1=tmp;
int tmpx=0,tmpy=0;
for(int i=1;i<=step1;++i){
tmpx+=a;tmpy+=b;
if(dict.find(pair<int,int>(tmpx,tmpy))!=dict.end())return 0;
}
return -1;
//step1=floor(tmp);
}else return 0;
}else return 0;
}else{
step1=X/(double)(a);
if(step1<=0||(fabs(step1-floor(step1))>1e-8))return 0;
}
if(b==0){
if(Y==0){
double tmp=X/(double)(a);
if(tmp>0&&(fabs(tmp-floor(tmp))<1e-8)){
step1=tmp;
int tmpx=0,tmpy=0;
for(int i=1;i<=step1;++i){
tmpx+=a;tmpy+=b;
if(dict.find(pair<int,int>(tmpx,tmpy))!=dict.end())return 0;
}
return -1;
}else return 0;
}else return 0;
}else{
step2=Y/(double)(b);
if(step2<=0||(fabs(step2-floor(step2))>1e-8))return 0;
}
if(step1==step2){
//blabla
int tmpx=0,tmpy=0;
for(int i=1;i<=step1;++i){
tmpx+=a;tmpy+=b;
if(dict.find(pair<int,int>(tmpx,tmpy))!=dict.end())return 0;
}
return -1;
}
else{
return 0;
}
}
int qpow(int a,int x){
int ans=1;
for(;x;x>>=1,a=a*1ll*a%mod){
if(x&1)ans=ans*1ll*a%mod;
}
return ans;
}
int check4(int a,int b){
if(X==0&&Y==0)return -1;
int step1,step2;
if(a==0){
if(X==0){
double tmp=Y/(double)(b);
if(tmp>0&&(fabs(tmp-floor(tmp))<1e-8)){
step1=tmp;
int tmpx=0,tmpy=0;
for(int i=1;i<=step1;++i){
tmpx+=a;tmpy+=b;
if(dict.find(pair<int,int>(tmpx,tmpy))!=dict.end())return 0;
}
return 1;
//step1=floor(tmp);
}else return 0;
}else return 0;
}else{
step1=X/(double)(a);
if(step1<=0||(fabs(step1-floor(step1))>1e-8))return 0;
}
if(b==0){
if(Y==0){
double tmp=X/(double)(a);
if(tmp>0&&(fabs(tmp-floor(tmp))<1e-8)){
step1=tmp;
int tmpx=0,tmpy=0;
for(int i=1;i<=step1;++i){
tmpx+=a;tmpy+=b;
if(dict.find(pair<int,int>(tmpx,tmpy))!=dict.end())return 0;
}
return 1;
}else return 0;
}else return 0;
}else{
step2=Y/(double)(b);
if(step2<=0||(fabs(step2-floor(step2))>1e-8))return 0;
}
if(step1==step2){
//blabla
int tmpx=0,tmpy=0;
for(int i=1;i<=step1;++i){
tmpx+=a;tmpy+=b;
if(dict.find(pair<int,int>(tmpx,tmpy))!=dict.end())return 0;
}
return 1;
}
else{
return 0;
}
}
int gcd(int a,int b){
return b==0?a:gcd(b,a%b);
}
int F[600],FF[600][600];
int seq[100],cnt=0;
int BASE=250000;
int q[500005];
bool dfn[500005];
bool block[500005];
bool legal(int x){
return x>=0&&x<500005;
}
int sum1[500005],sum2[500005];
int cir[500005],T;
bool dfn2[500005];
int fff[500005];
int check3(int a,int b,int to){
b=-b;
memset(cir,0,sizeof(cir));
memset(dfn,0,sizeof(dfn));
memset(block,0,sizeof(block));
memset(sum1,0,sizeof(sum1));memset(sum2,0,sizeof(sum2));
for(int i=1;i<=cnt;++i)block[seq[i]+BASE]=true;
for(int i=1;i<500005;++i){
if(i>=a){
sum1[i]=sum1[i-a]+(block[i]);
}
else{
sum1[i]=(block[i]);
}
if(i>=b){
sum2[i]=sum2[i-b]+(block[i]);
}else{
sum2[i]=(block[i]);
}
}
++T;
for(int i=a*b+a+b;i<500005;++i){
if(sum1[i]-sum1[i-a*b-a]==0&&sum2[i]-sum2[i-a*b-b]==0)cir[i]=true;
}
int head=0,tail=0;dfn[BASE]=true;
q[tail++]=BASE;
while(head!=tail){
int x=q[head++];
if(legal(x+a)&&!dfn[x+a]&&!block[x+a]){
dfn[x+a]=true;q[tail++]=x+a;
}
if(legal(x-b)&&!dfn[x-b]&&!block[x-b]){
dfn[x-b]=true;q[tail++]=x-b;
}
}
if(!dfn[BASE+to])return 0;
memset(dfn2,0,sizeof(dfn2));
head=tail=0;dfn2[BASE+to]=true;
q[tail++]=BASE+to;
while(head!=tail){
int x=q[head++];
if(legal(x-a)&&!dfn2[x-a]&&!block[x-a]){
dfn2[x-a]=true;q[tail++]=x-a;
}
if(legal(x+b)&&!dfn2[x+b]&&!block[x+b]){
dfn2[x+b]=true;q[tail++]=x+b;
}
}
for(int i=0;i<500005;++i){
if(cir[i]&&dfn[i]&&dfn2[i]){
return -1;
}
}memset(dfn,0,sizeof(dfn));
memset(fff,0,sizeof(fff));fff[BASE]=1;
head=0,tail=0;dfn[BASE]=true;
q[tail++]=BASE;
while(head!=tail){
int x=q[head++];
if(legal(x+a)&&!dfn[x+a]&&!block[x+a]){
fff[x+a]=(fff[x+a]+fff[x])%mod;
dfn[x+a]=true;q[tail++]=x+a;
}
if(legal(x-b)&&!dfn[x-b]&&!block[x-b]){
fff[x-b]=(fff[x-b]+fff[x])%mod;
dfn[x-b]=true;q[tail++]=x-b;
}
}
return fff[BASE+to];
}
int check2(){//方向相同,可以同向,也可以反向
if(ax==0){
if(X!=0)return 0;
if((ay>0)==(by>0)){
//同向
int gy=gcd(ay,by);
memset(F,0,sizeof(F));
if(Y%gy!=0||Y/gy<0)return 0;
int A=ay/gy,B=by/gy;
F[0]=1;
for(int i=0;i<=Y/gy;++i){
if(dict.find(pair<int,int>(0,gy*i))!=dict.end())F[i]=0;
F[i+A]=(F[i+A]+F[i])%mod;F[i+B]=(F[i+B]+F[i])%mod;
}
return F[Y/gy];
}else{
//反向
int gy=gcd(fabs(ay),fabs(by));
if(Y%gy!=0)return 0;
cnt=0;
for(int i=1;i<=K;++i){
if(xx[i]==0&&yy[i]%gy==0){
seq[++cnt]=yy[i]/gy;
}
}
int A=ay/gy,B=by/gy;
if(A>0)return check3(A,B,Y/gy);
else return check3(B,A,Y/gy);
}
}else if(ay==0){
if(Y!=0)return 0;
if((ax>0)==(bx>0)){
//同向
int gx=gcd(ax,bx);
memset(F,0,sizeof(F));
if(X%gx!=0||X/gx<0)return 0;
int A=ax/gx,B=bx/gx;
F[0]=1;
for(int i=0;i<=X/gx;++i){
if(dict.find(pair<int,int>(gx*i,0))!=dict.end()){
F[i]=0;
}
F[i+A]=(F[i+A]+F[i])%mod;F[i+B]=(F[i+B]+F[i])%mod;
}
return F[X/gx];
}else{
//反向
int gx=gcd(fabs(ax),fabs(bx));
if(X%gx!=0)return 0;
cnt=0;
for(int i=1;i<=K;++i){
if(yy[i]==0&&xx[i]%gx==0){
seq[++cnt]=xx[i]/gx;
}
}
int A=ax/gx,B=bx/gx;
if(A>0)return check3(A,B,X/gx);
else return check3(B,A,X/gx);
}
}else{
if((ax>0)==(bx>0)){
//同向
int gx=gcd(ax,bx),gy=gcd(ay,by);
if(X%gx!=0||X/gx<0)return 0;
if(Y%gy!=0||Y/gy<0)return 0;
if(X/gx!=Y/gy)return 0;
int A=ax/gx,B=bx/gx;
memset(F,0,sizeof(F));
F[0]=1;
F[0]=1;
for(int i=0;i<=X/gx;++i){
if(dict.find(pair<int,int>(gx*i,gy*i))!=dict.end()){
F[i]=0;
}
F[i+A]=(F[i+A]+F[i])%mod;F[i+B]=(F[i+B]+F[i])%mod;
}
return F[X/gx];
}else{
//反向
int gx=gcd(fabs(ax),fabs(bx)),gy=gcd(fabs(ay),fabs(by));
if(X%gx!=0)return 0;
if(Y%gy!=0)return 0;
if(X/gx!=Y/gy)return 0;
cnt=0;
int A=ax/gx,B=bx/gx;
for(int i=1;i<=K;++i){
if(yy[i]%gy==0&&xx[i]%gx==0&&yy[i]/gy==xx[i]/gx){
seq[++cnt]=xx[i]/gx;
}
}
if(A>0)return check3(A,B,X/gx);
else return check3(B,A,X/gx);
}
}
//同向:一定无环,递推一波即可
//反向:可能有环...
}
int fac[500005],inv[500005];
void init(){
fac[0]=1;
for(int i=1;i<500005;++i)fac[i]=fac[i-1]*1ll*i%mod;
inv[0]=1;
inv[1]=1;
for(int i=2;i<500005;++i)inv[i]=inv[mod%i]*1ll*(mod-mod/i)%mod;
for(int i=2;i<500005;++i){
inv[i]=inv[i-1]*1ll*inv[i]%mod;
}
}
int C(int n,int m){
return fac[n]*1ll*inv[m]%mod*inv[n-m]%mod;
}
int calc(int i,int j){
int dlt1=xx[j]-xx[i],dlt2=yy[j]-yy[i];
//double step1=,step2=;
double step2=(dlt1*1.0*ay-dlt2*1.0*ax)/(bx*1.0*ay-by*1.0*ax);
double step1=(dlt1*1.0*ay-step2*bx*ay)/ax/ay;
//必然有解.无解状况已经排除.
if(step1<0||step2<0)return 0;
if(fabs(step1-floor(step1))>1e-8||fabs(step2-floor(step2))>1e-8)return 0;
int n=step1,m=step2;
return C(n+m,m);
}
int f[20][2];bool vis[20];
int g[20][20],deg[20];
int main(){
freopen("knightmov.in","r",stdin);
freopen("knightmov.out","w",stdout);
int tests;scanf("%d",&tests);
init();
while(tests--){
scanf("%d%d%d",&X,&Y,&K);
scanf("%d%d%d%d",&ax,&ay,&bx,&by);
for(int i=1;i<=K;++i)scanf("%d%d",xx+i,yy+i);
if(ax==0&&ay==0&&bx==0&&by==0){
if(X==0&Y==0){
printf("-1
");
}else{
printf("0
");
}
continue;
}
dict.clear();
for(int i=1;i<=K;++i)dict.insert(pair<int,int>(xx[i],yy[i]));
if(ax==bx&&ay==by){
printf("%d
",check4(ax,ay));
}
else if(ax==0&&ay==0){
printf("%d
",check1(bx,by));
}else if(bx==0&&by==0){
printf("%d
",check1(ax,ay));
}else{
double d1=direc(ax,ay),d2=direc(bx,by);
if(d1==d2){
printf("%d
",check2());
}else{
if(X==0&&Y==0){
printf("1
");continue;
}else{
memset(f,0,sizeof(f));
xx[0]=0;yy[0]=0;xx[K+1]=X;yy[K+1]=Y;
f[0][0]=1;
for(int i=1;i<=K+1;++i)vis[i]=false;vis[0]=false;
memset(g,0,sizeof(g));memset(deg,0,sizeof(deg));
for(int i=0;i<=K+1;++i){
for(int j=0;j<=K+1;++j){
if(i!=j){
g[i][j]=calc(i,j);
if(g[i][j])deg[j]++;
}
}
}
for(int i=0;i<=K+1;++i){
int x=0x7f7f7f7f;
for(int j=0;j<=K+1;++j){
if(deg[j]==0&&!vis[j]){
x=j;break;
}
}
if(x==0x7f7f7f7f)break;
vis[x]=true;
for(int t=0;t<=K+1;++t){
if(g[x][t]){
deg[t]--;
f[t][1]=(f[t][1]+f[x][0]*1ll*g[x][t]%mod)%mod;
f[t][0]=(f[t][0]+f[x][1]*1ll*g[x][t]%mod)%mod;
}
}
}
printf("%d
",(f[K+1][1]-f[K+1][0]+mod)%mod);
}
}
}
}
// fclose(stdin);fclose(stdout);
return 0;
}
/*
3
3 3 0
1 2 2 1
9 9 2
1 2 2 1
1 2 6 6
1 1 0
0 0 0 0
*/