Given a 32-bit signed integer, reverse digits of an integer.
Example 1:
Input: 123
Output: 321
Example 2:
Input: -123
Output: -321
Example 3:
Input: 120
Output: 21
Note:
Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
这道题目考察了字符的反转,注意点是,我们需要进行判断是否溢出,我们直接强制转换一下即可
class Solution { public: int reverse(int x) { long ans = 0; while(x != 0) { ans = ans * 10 + x % 10; x /= 10; } return (int)ans == ans ? ans: 0; } };