Leetcode-Palindrome Partitioning II

Given a string s, partition s such that every substring of the partition is a palindrome.

Return the minimum cuts needed for a palindrome partitioning of s.

For example, given s = "aab",
Return 1 since the palindrome partitioning ["aa","b"] could be produced using 1 cut.

Analysis:

DP

Solution:

public class Solution {
    public int minCut(String s) {
        if (s.length()==0) return 0;

        int[] minCut = new int[s.length()+1];
        minCut[0] = -1;
        boolean[][] valid = new boolean[s.length()][s.length()];        
        for (int i=0;i<s.length();i++){
            valid[i][i]=true;
        }        

        for (int i=1;i<=s.length();i++){
            minCut[i] = minCut[i-1]+1;
            for (int j=i-2;j>=0;j--)
                if (s.charAt(j)==s.charAt(i-1) && (j==i-2 || valid[j+1][i-2])){
                    valid[j][i-1]=true;
                    minCut[i] = Math.min(minCut[i],minCut[j]+1);
                }
                
        }

        return minCut[s.length()];
    }

}