Find the Difference
Given two strings s and t which consist of only lowercase letters.
给出两个字符串,s和t,都是只有小写字母组成的。
String t is generated by random shuffling string s and then add one more letter at a random position.
字符串t是由字符串s其中在随机的位置添加一个字符组成的。
Find the letter that was added in t.
找出在t中增加的字符
Example:
Input: s = "abcd" t = "abcde" Output: e Explanation: 'e' is the letter that was added.
我一开始的想法就是把每个字符加起来,然后连个字符串相差的字符对应的数,就是对应的不同的字符了,很难说明白就直接看代码好了。
char c = 0;
for (int i=0;i<t.length();i++)
{
c += t.charAt(i);
}
for (int i=0;i<s.length();i++)
{
c -= s.charAt(i);
}
return c
之后看了讨论区,发现有一个异或好方法,但是无论怎么想都没想通。只能先记下了。
public char findTheDifference(String s, String t) { char c = 0; for (int i = 0; i < s.length(); ++i) { c ^= s.charAt(i); } for (int i = 0; i < t.length(); ++i) { c ^= t.charAt(i); } return c; }