• A1058 A+B in Hogwarts (20)(20 分)


    A1058 A+B in Hogwarts (20)(20 分)

    If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 10^7^], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

    Input Specification:

    Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

    Output Specification:

    For each test case you should output the sum of A and B in one line, with the same format as the input.

    Sample Input:

    3.2.1 10.16.27
    

    Sample Output:

    14.1.28
    

    AC代码

    #include <stdio.h>
    int main() {
        int a[3], b[3], c[3];
        scanf("%d.%d.%d %d.%d.%d", &a[0], &a[1], &a[2], &b[0], &b[1], &b[2]);
        int carry = 0;//进位 
        c[2] = (a[2] + b[2]) % 29;//二号位结果 
        carry = (a[2] + b[2]) / 29;//进位 
        c[1] = (a[1] + b[1] + carry) % 17;//一号位结果(加上进位) 
        carry = (a[1] + b[1] + carry) / 17;//进位 
        c[0] = a[0] + b[0] + carry;//无限制,不必再处理进位了 
        printf("%d.%d.%d", c[0], c[1], c[2]);
        return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/lingr7/p/9393318.html
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