描述
Given an array S of n integers, find three integers in S such that the sum is closest to
a given number, target. Return the sum of the three integers. You may assume that
each input would have exactly one solution. For example, given array S = -1 2 1 -4,
and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
思路
1、排序数组
2、循环遍历数组,两面夹逼
空间复杂度O(1),时间复杂度O(n2)
代码
package com.lilei.spring_boot_db.boot.pack1115; import java.util.Arrays; public class sum3closest { public static void main(String[] args) { int[] array = new int[]{1,2,3,4,5,6,7,9}; System.out.println(sum(array,25)); } static int sum(int[] array, int target) { int result = Integer.MIN_VALUE; Arrays.sort(array); for (int i = 0; i < array.length; i++) { int left = 0; int right = array.length - 1; while (left < right) { if (left != i && right != i) { if (Math.abs(target - result) > Math.abs(target - (array[left] + array[i] + array[right]))) result = array[left] + array[i] + array[right]; if (array[left] + array[i] + array[right] < target) { left++; } else if (array[left] + array[i] + array[right] > target) { right--; } else { return array[left] + array[i] + array[right]; } } else if (left == i) left++; else right--; } } return result; } }