Add a third dimension of time to a hashmap , so ur hashmap will look something like this - HashMap<K, t, V> where t is a float value. Implement the get and put methods to this map. The get method should be something like - map.get(K,t) which should give us the value. If t does not exists then map should return the closest t' such that t' is smaller than t. For example, if map contains (K,1,V1) and (K,2,V2) and the user does a get(k,1.5) then the output should be v1 as 1 is the next smallest number to 1.5
Uber, Google
解法:用HashMap记录key和TreeMap,TreeMap记录Time和Value,之所以用TreeMap是因为当没有这个时间时找到比给的时间小中的最大的。
floorkey method is used to return the greatest key less than or equal to the given key, or null if there is no such key.
Java:
public class TimeHashMap<Key, Time, Value> { private HashMap<Key, TreeMap<Time, Value>> map = new HashMap<Key, TreeMap<Time, Value>>(); public Value get(Key key, Time time) { final TreeMap<Time, Value> redBlackBST = map.get(key); if (redBlackBST == null) return null; final Time floorKey = redBlackBST.floorKey(time); return floorKey == null ? null : redBlackBST.get(floorKey); } public void put(Key key, Time time, Value value) { if (!map.containsKey(key)) { map.put(key, new TreeMap<Time, Value>()); } map.get(key).put(time, value); } public static void main(String args[]){ TimeHashMap<String, Double, String> data = new TimeHashMap<String, Double, String>(); data.put("K",1.0,"K1"); data.put("K",2.0,"K2"); System.out.println(data.get("K",0.9)); System.out.println(data.get("K",1.0)); System.out.println(data.get("K",1.5)); System.out.println(data.get("K",2.0)); System.out.println(data.get("K",2.2)); } }