• POJ 3916:Duplicate Removal 将相近的重复元素删除


    Duplicate Removal
    Time Limit: 1000MS   Memory Limit: 65536K
    Total Submissions: 1745   Accepted: 1213

    Description

    The company Al's Chocolate Mangos has a web site where visitors can guess how many chocolate covered mangos are in a virtual jar. Visitors type in a guess between 1 and 99 and then click on a "Submit" button. Unfortunately, the response time from the server is often long, and visitors get impatient and click "Submit" several times in a row. This generates many duplicate requests. 
    Your task is to write a program to assist the staff at ACM in filtering out these duplicate requests.

    Input

    The input consists of a series of lines, one for each web session. The first integer on a line is N, 0 < N ≤ 25, which is the number of guesses on this line. These guesses are all between 1 and 99, inclusive. The value N = 0 indicates the end of all the input.

    Output

    For each input data set, output a single line with the guesses in the original order, but with consecutive duplicates removed. Conclude each output line with the dollar sign character '$'. Note that there is a single space between the last integer and the dollar sign.

    Sample Input

    5 1 22 22 22 3
    4 98 76 20 76
    6 19 19 35 86 86 86
    1 7
    0

    Sample Output

    1 22 3 $
    98 76 20 76 $
    19 35 86 $
    7 $

    题意是将相近的重复元素删除。

    代码:

    #include <iostream>
    #include <algorithm>
    #include <cmath>
    #include <vector>
    #include <string>
    #include <cstring>
    #include <set>
    #pragma warning(disable:4996)
    using namespace std;
    
    vector<int>a;
    int num;
    
    int main()
    {
    	int i,temp;
    	while(cin>>num)
    	{
    		if(num==0)
    			break;
    		a.clear();
    		for(i=1;i<=num;i++)
    		{
    			cin>>temp;
    			a.push_back(temp);
    		}
           
    		vector<int>::iterator iter =unique(a.begin(),a.end());  
            a.erase(iter,a.end()); 
    		for(i=0;i<a.size();i++)
    		{
    			cout<<a[i]<<" ";
    		}
    		cout<<"$"<<endl;
    	}
    	return 0;
    }
    


    版权声明:本文为博主原创文章,未经博主允许不得转载。

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  • 原文地址:https://www.cnblogs.com/lightspeedsmallson/p/4899547.html
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