递归算法easy题
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: TreeNode* mergeTrees(TreeNode* t1, TreeNode* t2) { if(t1 == NULL) { return t2; } if(t2 == NULL) {} return t1; } auto ans = new TreeNode(t1->val + t2->val); ans->left = mergeTrees(t1->left, t2->left); ans->right = mergeTrees(t1->right, t2->right); return ans; } };