面向对象的程序设计_第二次作业 3月19日

第一题

//	一 
//	测试样例：11 12 13 11 11 11 11 10 9 13 13 11 16 14 15
//	测试样例：11 11 11 11 11 11 11 11 11 11 11 11 11 11 11
#include <iostream>
#include <iomanip>
#include <algorithm>

using namespace std;

//	输入n个温度
void inputTemps(int temp[], int n) {
	cout << "Please input the temperatures:" << endl;
	for (int i = 0; i < 15; ++i)
		cin >> temp[i];
	cout << endl;
}

//	显示柱状图
void displayTemps(int temp[], int n) {
	cout << "显示柱状图如下:" << endl;
	for (int i = 0; i < 15; ++i) {
		cout << left << setw(10) << i + 1;
		for (int j = 0; j < temp[i]; ++j)
			cout << '*';
		cout << endl;
	}
	cout << endl;
}

//	显示月间温度中的所有峰值
void displayPeaks(int temp[], int n) {
	cout << "显示峰值如下:" << endl;
	bool flag = 0;
	for (int i = 1; i < 14; ++i)
		if (temp[i] > temp[i - 1] && temp[i] > temp[i + 1]) {
			cout << "Max at day " << i + 1 << " is " << temp[i] << endl;
			flag = 1;
		}
	if (!flag)
		cout << "没有峰值" << endl;
	cout << endl;
}

//	显示月间持续最久的温度
void displayFlat(int temp[], int n) {
	cout << "显示崮的长度如下:" << endl;
	int max_len = 1;
	int length = 1;
	int before = temp[0];
	for (int i = 1; i < 15; ++i) {
		if (before == temp[i]) {
			++length;
			before = temp[i];
			if(i == 14)	//	特殊极端情况的一个判定
				max_len = max(length, max_len);
			continue;
		}
		before = temp[i];
		max_len = max(length, max_len);
		length = 1;
	}
	cout << "The length of longest flat is " << max_len << endl;
}

//	主函数
int main() {
	int temps[30];

	inputTemps(temps, 30);
	displayTemps(temps, 30);
	displayPeaks(temps, 30);
	displayFlat(temps, 30);

	return 0;
}

 第二题

// 二
////	测试样例：11 12 -13 11 11 11 11 -10 9 13 13 11 16 14 15
////	测试样例：-11 11 11 11 11 11 11 11 11 11 11 11 11 11 11
#include <iostream>
#include <iomanip>
#include <algorithm>

using namespace std;

//	输入n个温度
void inputTemps(int temp[], int n) {
	cout << "Please input the temperatures:" << endl;
	for (int i = 0; i < 15; ++i)
		cin >> temp[i];
	cout << endl;
}

//	显示柱状图
void displayTemps(int temp[], int n) {
	cout << "显示柱状图如下:" << endl;
	for (int i = 0; i < 15; ++i) {
		char print[100] = { ' ' };
		print[31] = '|';
		cout << left << setw(10) << temp[i];
		if (temp[i] > 0) {
			for (int j = 32; j < temp[i] + 32; ++j) {
				print[j] = '*';
			}
		}
		else {
			for (int j = 30; j > 30 + temp[i]; --j) {
				print[j] = '*';
			}
		}
		for (int k = 0; k < 100; ++k)
			cout << print[k];
		cout << endl;
	}
	cout << endl;
}

void displayNum(int temp[], int n) {
	sort(temp, temp + 15);
	int before = temp[0];
	int len = 1;
	int max_num = 1;
	int num = temp[0];
	for (int i = 1; i < 15; ++i) {
		if (before == temp[i]) {
			len++;
			before = temp[i];
			if (i == 14) {
				if (len > max_num)
					num = temp[i - 1];
				max_num = max(len, max_num);
			}		
			continue;
		}
		
		if (len > max_num)
			num = temp[i - 1];
		max_num = max(len,max_num);
		len = 1;
		before = temp[i];
	}
	cout << "出现次数最多的是" << num << "度，出现了" << max_num << "次";
}

int main()
{
	int temps[30];
	inputTemps(temps, 30);
	displayTemps(temps, 30);
	displayNum(temps, 30);

	return 0;
}

 第三题

// 三
// 测试样例：2 3 BBWBEWW 4 WWWWBBEBB

#include <iostream>
#include <algorithm>

using namespace std;

int main()
{
	
	int N = 0;
	cin >> N;
	for(int k = 1;k <= N; ++k){
		char str[1000] = {' '};
		int n = 0;
		cin >> n;
		int temp = 0;
		bool flag = 1;
		for (int i = 1; i <= 2 * n + 1; ++i) {
			cin >> str[i];
			if (str[i] == 'E')
				temp = i;
			if (str[i] == 'B' && i < n)
				flag = 0;
		}
		cout << "结果_" << k << endl;
		if (flag)
			cout << "目标格局" << endl;
		else{
			if (temp != 2 * n + 1) {
				swap(str[temp], str[temp + 1]);
				cout << str << endl;
				swap(str[temp], str[temp + 1]);
				if (temp != 2 * n) {
					swap(str[temp], str[temp + 2]);
					cout << str << endl;
					swap(str[temp], str[temp + 2]);
					if (temp != 2 * n - 1) {
						swap(str[temp], str[temp + 3]);
						cout << str << endl;
						swap(str[temp], str[temp + 3]);
					}
				}
			}
			if (temp != 1) {
				swap(str[temp], str[temp - 1]);
				cout << str << endl;
				swap(str[temp], str[temp - 1]);
				if (temp != 2) {
					swap(str[temp], str[temp - 2]);
					cout << str << endl;
					swap(str[temp], str[temp - 2]);
					if (temp != 3) {
						swap(str[temp], str[temp - 3]);
						cout << str << endl;
						swap(str[temp], str[temp - 3]);
					}
				}
			}
		}
	}
}