• A1093. Count PAT's (25)


    The string APPAPT contains two PAT's as substrings. The first one is formed by the 2nd, the 4th, and the 6th characters, and the second one is formed by the 3rd, the 4th, and the 6th characters.

    Now given any string, you are supposed to tell the number of PAT's contained in the string.

    Input Specification:

    Each input file contains one test case. For each case, there is only one line giving a string of no more than 105characters containing only P, A, or T.

    Output Specification:

    For each test case, print in one line the number of PAT's contained in the string. Since the result may be a huge number, you only have to output the result moded by 1000000007.

    Sample Input:

    APPAPT
    

    Sample Output:

    2
    

    提交代码

     1 #include <cstdlib>
     2 #include <iostream>
     3 #include <algorithm>
     4 #include <string.h>
     5 #include <vector>
     6 #include <set>
     7 using namespace std;
     8 
     9 int main(int argc, char *argv[])
    10 {
    11     
    12     char s[100010];
    13     gets(s);
    14 long long count=0;
    15     int len=strlen(s);
    16     if(len==0)
    17     {
    18         printf("0");
    19         system("PAUSE");
    20         return 0;
    21      }  
    22     int countt=0; 
    23      for(int i=0;i<len;i++)
    24     {
    25     if(s[i]=='T')countt++;
    26     } 
    27 int countp=0;
    28     for(int i=0;i<len;i++)
    29 {
    30 if(s[i]=='P')countp++;
    31 if(s[i]=='A')count+=countp*countt;
    32 if(s[i]=='T')countt--;
    33 }
    34      printf("%lld",count%1000000007);
    35     system("PAUSE");
    36    
    37     
    38     return EXIT_SUCCESS;
    39 }
  • 相关阅读:
    webstorm 取消拖动代码
    可读流
    页面上怎么使用svg
    从element-ui按需引入去探索
    vue组件库用markdown生成文档
    create-react-app中的babel配置探索
    svg 使用中的疑惑点
    express中是如何处理IP的?
    koa中是如何封装获取客户端IP的?
    博客园文章添加目录
  • 原文地址:https://www.cnblogs.com/ligen/p/4338425.html
Copyright © 2020-2023  润新知