A1065. A+B and C (64bit) (20)

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: false
Case #2: true
Case #3: false

#include <stdio.h>
#include <stdlib.h>
#include <iostream>
#include <string.h>
#include <string>
#include <math.h>
#include <algorithm>
using namespace std;


int main(){
  
   int t,tcase=1;
   scanf("%d",&t);
   while(t--)
   {
       long long a,b,c;
       scanf("%lld %lld %lld",&a,&b,&c);
       long long res=a+b;
       bool flag;
       if(a>0&&b>0&&res<0)flag=true;
       else if(a<0&&b<0&&res>=0)flag=false;
       else if(res>c)flag=true;
       else flag=false;
       if(flag==true)
       {
           printf("Case #%d: true
",tcase++);
       }else
       {
           printf("Case #%d: false
",tcase++);
       }
   } 
    return 0;
}