• python 计算器


    import re
    from functools import reduce

    '''
    分析:
    1.用户输入
    2.判断表达式是否正确
    3.计算
    1)通过正则获取(。。。)进行计算并替换(。。。)
    2)循环1)直到未找到则标记为最后一层,计算结果并返回
    计算中的注意事项:
    注意两个数的前后位置,不要颠倒了
    查找含有负数的符号,进行转换(查找负数符号最前面的-或+进行倒换,并去掉负数符号)
    4.显示结果
    '''
    def count(first,symbol,second):
    '''
    计算两个数的运算值
    :param first: 第一个数
    :param symbol: 运算符
    :param second: 第二个数
    :return:
    '''
    if symbol == '*':
    return float(first) * float(second)
    elif symbol=='/':
    return float(first) / float(second)
    elif symbol=='+':
    return float(first) + float(second)
    elif symbol == '-':
    return float(first) - float(second)

    def count_express(group):

    '''
    计算一个字符表达式的值
    :param group: 要运算的字符
    :return:
    '''
    result = re.findall('[0-9]+[.0-9]*|[^0-9]', group)
    list1 = list(reversed(list(result)))
    first = ''
    symbol = '+'
    second = '0'
    first = list1.pop()
    stack =[]
    # '1+2*(2+3*4-4)'
    if first == '-':
    first += list1.pop()
    while len(list1) != 0:
    symbol = list1.pop()
    second = list1.pop()
    if symbol == '-' or symbol == '+':
    stack.append(first)
    stack.append(symbol)
    first = second
    continue
    first = str(count(first, symbol, second))
    while len(stack) > 1:
    symbol = stack.pop()
    second = stack.pop()
    first = count(second, symbol, first)
    return str(first)
    def group_count(express):
    '''
    计算表达式值
    :param express: 字符表达式
    :return:
    '''

    while True:
    pattern = r'([^()]+)'
    pat = re.compile(pattern)
    group = pat.search(express)
    result = []
    # 判断是否找到()
    flag = True
    if group != None:
    group = group.group()
    group = group.replace('(','').replace(')','')
    else:
    group = express
    flag = False
    result = count_express(group)
    # 如果是最后一层,直接返回值
    if flag is False:
    return result
    # 将express中找到(..)的运算结果进行替换
    express = pat.sub(result,express)
    express = replace_symbol(express)
    print(express)
    def replace_symbol(express):
    '''
    将负数转正
    :param express:
    :return:
    '''
    split_list = re.split('[+*/-]-', express)
    b = split_list[0]
    # 字符反转
    c = reduce(lambda x, y: y + x, b)
    # 查找离要负号位最近是(+-)进行替换
    d = re.search('[+-]', c)
    f = d.group()
    m = '+' if f == '-' else '-'
    list_str = list(c)
    list_str[d.span()[0]] = m
    list_str.reverse()
    c = ''.join(list_str)
    return c +express[len(c)]+ split_list[1]
    def check_express(express):
    '''
    校验输入的表达式是否正确
    :param express: 字符表达式
    :return:
    '''
    pattern1 = '[^0-9+*/.()-]|[^0-9][+/*.]|[0-9][(]|^[+/*.]|[+/*.]$'
    result = re.search(pattern1,express)
    return result

    def input_express():
    # express = input("请输入(只能包含0-9+-*/.()字符):")
    express = '-1+2*3-4/(-10*2)-3'
    express = re.sub(' ', '', express)
    result = check_express(express)
    if result != None:
    span = str(result.span())
    group = str(result.group())
    print('输入了错误的字符或表达式格式不对,所在位置:%s,错误字符:%s' % (span, group))
    sys.exit(0)
    return express

    if __name__ == '__main__':
    express = input_express()
    result = group_count(express)
    print('结果:%s' %result)
  • 相关阅读:
    【转】Geary's C
    ArcGIS中影像与影像,影像与点云之间的配准
    [转] EPSG CODE的含义
    地图投影
    【从翻译mos文章】oracle linux 和外部存储系统 关系
    找呀志_使用SQLiteDatabase增删改提供的搜索方法和事务
    [049] 微信公众平台视频公开课1说话-基础知识
    我看到西电通院考试——学生应该做的事情?
    使用 Eclipse 的 SVN 主要插件创建项目/支/标签
    【SSH三个框架】Hibernate第十篇基础:inverse属性具体解释
  • 原文地址:https://www.cnblogs.com/lides/p/11126841.html
Copyright © 2020-2023  润新知