• javascript数组操作方法


    1.join('+')

    功能: 1.数组转字符串,可以修改连接符

    原素组:不改变

    返回值:增加连接符的字符串

    let list = ['a', 12, 'c', 'd', 'e'];
    let result = list.join(' - ');
    console.log('old result', list) //["a", 12, "c", "d", "e"]
    console.log('new result', result) //"a - 12 - c - d - e"

    2.reverce()

    功能:反转数组

    原数组:反转

    返回值: 反转

    let list = ['a', 12, 'c', 'd', 'e'];
    let result = list.reverse();
    console.log('old result', list) //["e", "d", "c", 12, "a"]
    console.log('new result', result) //["e", "d", "c", 12, "a"]

    3.push()

    功能:在数组末尾增加1个或多个元素

    原数组:增加

    返回值:数组增加后的长度

    let list = ['a'];
    let result = list.push('b','c');
    console.log('old result', list) // ["a", "b", "c"]
    console.log('new result', result) //3

    4.pop()

    功能:在数组末尾删除一个元素

    原数组:减少

    返回值:删除的元素

    let list = ['a','b'];
    let result = list.pop();
    console.log('old result', list)    // ["a"]
    console.log('new result', result)  //  b

    5.unshift()

    功能:在数组前端增加一个元素

    原数组:改变原数组

    返回值:增加后数组长度

    let list = ['a','b'];
    let result = list.unshift('0','1');
    console.log('old result', list) // ["0", "1", "a", "b"]
    console.log('new result', result) //4

    6.shift

    功能:在数组前端删除一个元素

    原数组:改变原数组

    返回值:删除的元素

    let list = ['a','b'];
    let result = list.shift();
    console.log('old result', list) // ["b"]
    console.log('new result', result) // a

    7.slice(begin,end)

    功能:截取字符串,begin开始下标,到end下标且不包含end元素,浅拷贝

    原数组:不改变原数组

    返回值:截取到的数组

    let list = ['a','b','c','d','e'];
    let result = list.slice(1,2);
    console.log('old result', list)  // ["a", "b", "c", "d", "e"]
    console.log('new result', result) // ["b"]

    8.splice(start,count,value)

    功能:可以截取可以增加功能强大,start下标开始截取count个元素,并使用value填充进去

    原数组:在原数组上进行操作

    返回值:截取到值的数组

    let list = ['Jan','March', 'April', 'June'];
    const result = list.splice(1, 1, 'Feb');
    console.log('old result', list) // ["Jan", "Feb", "April", "June"]
    console.log('new result', result) // ["March"]

    9.sort((a,b) => {return a - b})

    功能:数组排序

    原数组:改变原数组为排序后的数组

    返回值:排序后的数组

    let list = [{
                id: 2,
                msg: '老二'
                },
            {
                id: 1,
                msg: '老大'
            },
            {
                id: 4,
                msg: '老四'
            },
                   {
                id: 3,
               msg: '老三'
            }];
    let result = list.sort((a, b) => {
        return a.id - b.id;
    });
    console.log('old result', list) //[{id: 1, msg: "老大"},{id: 2, msg: "老二"},{id: 3, msg: "老三"},{id: 4, msg: "老四"}]
    console.log('new result', result)   //同上                       

    10.toString

    功能:数组转换为字符串

    原数组:不受影响

    返回值:转换字符串

    let list = ['Jan', 'March', 'April', 'June'];
    const result = list.toString();
    console.log('old result', list)  // ["Jan", "March", "April", "June"]
    console.log('new result', result) // Jan,March,April,June

    11.concat

    功能:合并数组

    原数组:不受影响

    返回值:合并后的新数组

    let list = ['Jan', 'March', 'April', 'June'];
    let list2 = [1,2,3]
    const result = list.concat(list2);
    console.log('old result', list) // ["Jan", "March", "April", "June"]
    console.log('new result', result) //["Jan", "March", "April", "June", 1, 2, 3]

    12.flat(depth)

    功能:数据扁平化处理,depth为扁平化的层数,默认为1层,infinity为无限多层

    原数组:不受影响

    返回值:扁平化后的新数组

    缺点:ECMAScript 2019 兼容性

    let list = [['飞机'],[1,2,3,[8,10]]];
    const result = list.flat(Infinity);
    console.log('old result', list) // 不变
    console.log('new result', result) //["飞机", 1, 2, 3, 8, 10]

    13.from()

    <ul>
        <li>1</li>
        <li>2</li>
        <li>3</li>
        <li>4</li>
        <li>5</li>
    </ul>
            <script type="text/javascript">
                let lis = document.querySelectorAll('li');
                const result = Array.from(lis);
                console.log('old result', lis)
                console.log('new result', result)
            </script>
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  • 原文地址:https://www.cnblogs.com/liangfc/p/12859193.html
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