题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1070
Milk
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 10484 Accepted Submission(s): 2497
Problem Description
Ignatius
drinks milk everyday, now he is in the supermarket and he wants to
choose a bottle of milk. There are many kinds of milk in the
supermarket, so Ignatius wants to know which kind of milk is the
cheapest.
Here are some rules:
1. Ignatius will never drink the milk which is produced 6 days ago or earlier. That means if the milk is produced 2005-1-1, Ignatius will never drink this bottle after 2005-1-6(inclusive).
2. Ignatius drinks 200mL milk everyday.
3. If the milk left in the bottle is less than 200mL, Ignatius will throw it away.
4. All the milk in the supermarket is just produced today.
Note that Ignatius only wants to buy one bottle of milk, so if the volumn of a bottle is smaller than 200mL, you should ignore it.
Given some information of milk, your task is to tell Ignatius which milk is the cheapest.
Here are some rules:
1. Ignatius will never drink the milk which is produced 6 days ago or earlier. That means if the milk is produced 2005-1-1, Ignatius will never drink this bottle after 2005-1-6(inclusive).
2. Ignatius drinks 200mL milk everyday.
3. If the milk left in the bottle is less than 200mL, Ignatius will throw it away.
4. All the milk in the supermarket is just produced today.
Note that Ignatius only wants to buy one bottle of milk, so if the volumn of a bottle is smaller than 200mL, you should ignore it.
Given some information of milk, your task is to tell Ignatius which milk is the cheapest.
Input
The
input contains several test cases. The first line of the input is a
single integer T which is the number of test cases. T test cases follow.
Each test case starts with a single integer N(1<=N<=100) which is the number of kinds of milk. Then N lines follow, each line contains a string S(the length will at most 100 characters) which indicate the brand of milk, then two integers for the brand: P(Yuan) which is the price of a bottle, V(mL) which is the volume of a bottle.
Each test case starts with a single integer N(1<=N<=100) which is the number of kinds of milk. Then N lines follow, each line contains a string S(the length will at most 100 characters) which indicate the brand of milk, then two integers for the brand: P(Yuan) which is the price of a bottle, V(mL) which is the volume of a bottle.
Output
For
each test case, you should output the brand of the milk which is the
cheapest. If there are more than one cheapest brand, you should output
the one which has the largest volume.
Sample Input
2
2
Yili 10 500
Mengniu 20 1000
4
Yili 10 500
Mengniu 20 1000
Guangming 1 199
Yanpai 40 10000
Sample Output
Mengniu
Mengniu
Hint
In the first case, milk Yili can be drunk for 2 days, it costs 10 Yuan. Milk Mengniu can be drunk for 5 days, it costs 20 Yuan. So Mengniu is the cheapest.In the second case,
milk Guangming should be ignored. Milk Yanpai can be drunk for 5 days, but it costs 40 Yuan. So Mengniu is the cheapest.Author
Ignatius.L
水水更健康。。。。这里注意下，牛奶最多只能喝5天，少于200ml的牛奶不算，如果最便宜的牛奶不止一种，那么得选容量最大的一个。。注意就算是牛奶容量大于5天能喝掉的量，也就是1000ml，也不能直接把多于1000ml的部分忽略。。
By LFENG
|
#include<cstdio>
#include<algorithm> #include<cstring> using namespace std; struct milk { int ml; int day; char name[105]; double price; }mi[105]; int n,m; bool cmp(milk a,milk b) { if(a.price!=b.price)return a.price<b.price; else if(a.price==b.price)return a.ml>b.ml; } void getdata() { int i,a; char s[105]; scanf("%d",&n); for(i=0,m=0;i<n;i++) { scanf("%s %d %d",mi[m].name,&a,&mi[m].ml); if(mi[m].ml<200)continue; mi[m].day=mi[m].ml/200; if(mi[m].day>5)mi[m].day=5; mi[m].price=a/mi[m].day; m++; } sort(mi,mi+m,cmp); } int main() { int t; scanf("%d",&t); getchar(); while(t--) { getdata(); printf("%s\n",mi[0].name); } return 0; } |