You are given a string q. A sequence of k strings s1, s2, ..., sk is called beautiful, if the concatenation of these strings is string q (formally, s1 + s2 + ... + sk = q) and the first characters of these strings are distinct.
Find any beautiful sequence of strings or determine that the beautiful sequence doesn't exist.
Input
The first line contains a positive integer k (1 ≤ k ≤ 26) — the number of strings that should be in a beautiful sequence.
The second line contains string q, consisting of lowercase Latin letters. The length of the string is within range from 1 to 100, inclusive.
Output
If such sequence doesn't exist, then print in a single line "NO" (without the quotes). Otherwise, print in the first line "YES" (without the quotes) and in the next k lines print the beautiful sequence of strings s1, s2, ..., sk.
If there are multiple possible answers, print any of them.
Examples
Input
1
abca
Output
YES
abca
Input
2
aaacas
Output
YES
aaa
cas
Input
4
abc
Output
NO
Note
In the second sample there are two possible answers: {"aaaca", "s"} and {"aaa", "cas"}.
#include<iostream>
#include<string>
#include<cstring>
#include<map>
#include<queue>
using namespace std;
map<char,int >wakaka;
int a[1010];
int main()
{
int n;
cin>>n;
memset(a,0,sizeof(a));
string s;
cin>>s;
int len=s.size();
if(len<n)
{
cout<<"NO"<<endl;
}
else
{
a[0]=0;
int ans=0;
for(int i=0; i<len; i++)
{
if(wakaka[s[i]]==0)
{
ans++;
a[ans]=i;
}
wakaka[s[i]]++;
}
if(ans>=n)
{
cout<<"YES"<<endl;
for(int i=1; i<=ans; i++)
{
if(i==n)
{
for(int j=a[i]; j<len; j++)
{
cout<<s[j];
}
break;
}
for(int j=a[i]; j<a[i+1]; j++)
{
cout<<s[j];
}
cout<<endl;
}
}
else
{
cout<<"NO"<<endl;
}
}
return 0;
}