方法一:使用for循环
int []pins = {9,3,7,2}
int []copy = new int[pins.length];
for(int i =0;i!=copy.length;i++)
{
copy[i] = pins[i];
}
方法二:使用数组对象中的CopyTo()方法
int []pins = {9,3,7,2}
int []copy2 = new int[pins.length];
pins.CopyTo(copy2,0);
方法三:使用Array类的一个静态方法Copy()
int []pins = {9,3,7,2}
int []copy3 = new int[pins.length];
Array.Copy(pins,copy3,copy.Length);
方法四:使用Array类中的一个实例方法Clone(),可以一次调用,最方便,但是Clone()方法返回的是一个对象,所以要强制转换成恰当的类类型。
int []pins = {9,3,7,2}
int []copy4 = (int [])pins.Clone();
方法五:
string[] student1 = { "$", "$", "c", "m", "d", "1", "2", "3", "1", "2", "3" };
string[] student2 = { "0", "1", "2", "3", "4", "5", "6", "6", "1", "8", "16","10","45", "37", "82" };
ArrayList student = new ArrayList();
foreach (string s1 in student1)
{
student.Add(s1);
}
foreach (string s2 in student2)
{
student.Add(s2);
}
string[] copyAfter = (string[])student.ToArray(typeof(string));
两个数组合并,最后把合并后的结果赋给copyAfter数组,这个例子可以灵活变通,很多地方可以用。