Description
Given a sorted linked list, delete all duplicates such that each element appear only once.
Example
Given 1->1->2, return 1->2.
Given 1->1->2->3->3, return 1->2->3.
思路
- 链表去重,一旦重复,留下一个节点
代码
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode* deleteDuplicates(ListNode* head) {
if(!head) return NULL;
ListNode *ptr = head, *pNext = head->next;
ListNode *res = new ListNode(0);
ListNode *h = res;
while(pNext){
if(ptr->val == pNext->val){
do{
ListNode *tmp = pNext;
pNext = pNext->next;
delete tmp;
}while(pNext && pNext->val == ptr->val);
}
res->next = ptr;
res = res->next;
ptr = pNext;
if(ptr)
pNext = ptr->next;
}
if(ptr && res && res->val != ptr->val){
res->next = ptr;
res = res->next;
}
res->next = NULL;
return h->next;
}
};