• 2. Add Two Numbers(链表尾插法)


    You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

    You may assume the two numbers do not contain any leading zero, except the number 0 itself.

    Example:

    Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
    Output: 7 -> 0 -> 8
    Explanation: 342 + 465 = 807.
    /**
     * Definition for singly-linked list.
     * public class ListNode {
     *     int val;
     *     ListNode next;
     *     ListNode(int x) { val = x; }
     * }
     */
    class Solution {
        public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
            ListNode list = null, s = null;
            int sum = 0;
            while (l1 != null || l2 != null) {
                sum /= 10;
                if (l1 != null) {
                    sum += l1.val;
                    l1 = l1.next;
                }
                if (l2 != null) {
                    sum += l2.val;
                    l2 = l2.next;
                }
                if (list == null) {
                    list = new ListNode(sum % 10);
                    s = list;
                } else {
                    ListNode node = new ListNode(sum % 10);
                    s.next = node;
                    s = s.next;
                }
            }
            if (sum / 10 == 1) {
                s.next = new ListNode(1);
            }
            return list;
        }
    }

    Debug code in playground:

    /* -----------------------------------
     *  WARNING:
     * -----------------------------------
     *  Your code may fail to compile
     *  because it contains public class
     *  declarations.
     *  To fix this, please remove the
     *  "public" keyword from your class
     *  declarations.
     */
    
    /**
     * Definition for singly-linked list.
     * public class ListNode {
     *     int val;
     *     ListNode next;
     *     ListNode(int x) { val = x; }
     * }
     */
    class Solution {
        public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
            ListNode list = null, s = null;
            int sum = 0;
            while (l1 != null || l2 != null) {
                sum /= 10;
                if (l1 != null) {
                    sum += l1.val;
                    l1 = l1.next;
                }
                if (l2 != null) {
                    sum += l2.val;
                    l2 = l2.next;
                }
                if (list == null) {
                    list = new ListNode(sum % 10);
                    s = list;
                } else {
                    ListNode node = new ListNode(sum % 10);
                    s.next = node;
                    s = s.next;
                }
            }
            if (sum / 10 == 1) {
                s.next = new ListNode(1);
            }
            return list;
        }
    }
    
    public class MainClass {
        public static int[] stringToIntegerArray(String input) {
            input = input.trim();
            input = input.substring(1, input.length() - 1);
            if (input.length() == 0) {
              return new int[0];
            }
        
            String[] parts = input.split(",");
            int[] output = new int[parts.length];
            for(int index = 0; index < parts.length; index++) {
                String part = parts[index].trim();
                output[index] = Integer.parseInt(part);
            }
            return output;
        }
        
        public static ListNode stringToListNode(String input) {
            // Generate array from the input
            int[] nodeValues = stringToIntegerArray(input);
        
            // Now convert that list into linked list
            ListNode dummyRoot = new ListNode(0);
            ListNode ptr = dummyRoot;
            for(int item : nodeValues) {
                ptr.next = new ListNode(item);
                ptr = ptr.next;
            }
            return dummyRoot.next;
        }
        
        public static String listNodeToString(ListNode node) {
            if (node == null) {
                return "[]";
            }
        
            String result = "";
            while (node != null) {
                result += Integer.toString(node.val) + ", ";
                node = node.next;
            }
            return "[" + result.substring(0, result.length() - 2) + "]";
        }
        
        public static void main(String[] args) throws IOException {
            BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
            String line;
            while ((line = in.readLine()) != null) {
                ListNode l1 = stringToListNode(line);
                line = in.readLine();
                ListNode l2 = stringToListNode(line);
                
                ListNode ret = new Solution().addTwoNumbers(l1, l2);
                
                String out = listNodeToString(ret);
                
                System.out.print(out);
            }
        }
    }

    这个不要理所当然想成了头插法,看到测试代码才知道是尾插法,返回的ListNode也是需要尾插法的。

    ========================Talk is cheap, show me the code=========================

    CSDN博客地址:https://blog.csdn.net/qq_34115899
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  • 原文地址:https://www.cnblogs.com/lcy0515/p/10807859.html
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