• 仅用一句SQL更新整张表的涨跌幅、涨跌率


    问题场景

    各大平台店铺的三项评分(物流、服务、商品)变化情况;
    商品每日价格的变化记录;
    股票的实时涨跌浮;
    

    复现场景

    表:主键ID,商品编号,记录时的时间,记录时的价格,创建时间。
    问题:获取每个商品每次的变化情况(涨跌幅、涨跌率)。
    

    解决思路

    1、要想高效率的更新涨跌,就肯定不能是逐条数据更新,要通过自连表建立起对应关系,将每一条数据关联到上一次的价格数据。

    2、由于数据库非常庞大,所以可能存在很多垃圾数据,就比如说相关的字段值为NULL或者非有效值的,这些数据要先排除掉。

    SELECT id,goods_code,goods_date,goods_price FROM test_goods_price_change WHERE goods_price IS NOT NULL AND goods_date IS NOT NULL;
    

    3、然后在获取每条数据的上一条数据,同样也要先排除掉垃圾数据。

    SELECT tmp_a.*, MAX(tmp_b.goods_date) AS last_date FROM 
    ( SELECT id,goods_code,goods_date,goods_price FROM test_goods_price_change WHERE goods_price IS NOT NULL AND goods_date IS NOT NULL ) AS tmp_a
    LEFT JOIN
    ( SELECT id,goods_code,goods_date,goods_price FROM test_goods_price_change WHERE goods_price IS NOT NULL AND goods_date IS NOT NULL ) AS tmp_b
    ON tmp_a.goods_code = tmp_b.goods_code AND tmp_a.goods_date > tmp_b.goods_date GROUP BY tmp_a.id;
    

    4、获取到上一条数据后,获取上条数据对应的商品价格。

    SELECT tmp_ab.*,tmp_c.goods_price AS last_price FROM 
    (
    	SELECT tmp_a.*, MAX(tmp_b.goods_date) AS last_date FROM 
    	( SELECT id,goods_code,goods_date,goods_price FROM test_goods_price_change WHERE goods_price IS NOT NULL AND goods_date IS NOT NULL ) AS tmp_a
    	LEFT JOIN
    	( SELECT id,goods_code,goods_date,goods_price FROM test_goods_price_change WHERE goods_price IS NOT NULL AND goods_date IS NOT NULL ) AS tmp_b
    	ON tmp_a.goods_code = tmp_b.goods_code AND tmp_a.goods_date > tmp_b.goods_date GROUP BY tmp_a.id
    ) AS tmp_ab 
    LEFT JOIN (SELECT id,goods_code,goods_date,goods_price FROM test_goods_price_change WHERE goods_price IS NOT NULL AND goods_date IS NOT NULL ) AS tmp_c
    ON tmp_ab.goods_code = tmp_c.goods_code AND tmp_c.goods_date = tmp_ab.last_date ORDER BY tmp_ab.id;
    

    5、获取到上条数据以及对应的价格后,开始进行计算,获取到最终的结果。

    SELECT 
    	*, 
    	(CONVERT(goods_price, DECIMAL(10,2)) - CONVERT(last_price, DECIMAL(10,2))) AS '涨跌幅',
    	ROUND((CONVERT(goods_price, DECIMAL(10,2)) - CONVERT(last_price, DECIMAL(10,2)))/CONVERT(last_price, DECIMAL(10,2)), 2) AS '涨跌率' 
    FROM (
    	SELECT tmp_ab.*,tmp_c.goods_price AS last_price FROM 
    	(
    		SELECT tmp_a.*, MAX(tmp_b.goods_date) AS last_date FROM 
    		( SELECT id,goods_code,goods_date,goods_price FROM test_goods_price_change WHERE goods_price IS NOT NULL AND goods_date IS NOT NULL ) AS tmp_a
    		LEFT JOIN
    		( SELECT id,goods_code,goods_date,goods_price FROM test_goods_price_change WHERE goods_price IS NOT NULL AND goods_date IS NOT NULL ) AS tmp_b
    		ON tmp_a.goods_code = tmp_b.goods_code AND tmp_a.goods_date > tmp_b.goods_date GROUP BY tmp_a.id
    	) AS tmp_ab 
    	LEFT JOIN (SELECT id,goods_code,goods_date,goods_price FROM test_goods_price_change WHERE goods_price IS NOT NULL AND goods_date IS NOT NULL ) AS tmp_c
    	ON tmp_ab.goods_code = tmp_c.goods_code AND tmp_c.goods_date = tmp_ab.last_date ORDER BY tmp_ab.id
    ) AS tmp
    

    解决方案

    -- 创建表SQL
    CREATE TABLE `test_goods_price_change` (
      `id` int(11) NOT NULL AUTO_INCREMENT COMMENT '主键ID',
      `goods_code` varchar(50) NOT NULL COMMENT '商品编码',
      `goods_date` int(11) NOT NULL COMMENT '记录时的时间',
      `goods_price` decimal(10,2) NOT NULL COMMENT '记录时的价格',
      `created_at` int(11) NOT NULL COMMENT '创建时间',
      PRIMARY KEY (`id`)
    ) ENGINE=InnoDB CHARSET=utf8mb4;
    
    -- 获取涨跌浮SQL
    SELECT 
    	*, 
    	(CONVERT(goods_price, DECIMAL(10,2)) - CONVERT(last_price, DECIMAL(10,2))) AS '涨跌幅',
    	ROUND((CONVERT(goods_price, DECIMAL(10,2)) - CONVERT(last_price, DECIMAL(10,2)))/CONVERT(last_price, DECIMAL(10,2)), 2) AS '涨跌率' 
    FROM (
    	SELECT tmp_ab.*,tmp_c.goods_price AS last_price FROM 
    	(
    		SELECT tmp_a.*, MAX(tmp_b.goods_date) AS last_date FROM 
    		( SELECT id,goods_code,goods_date,goods_price FROM test_goods_price_change WHERE goods_price IS NOT NULL AND goods_date IS NOT NULL ) AS tmp_a
    		LEFT JOIN
    		( SELECT id,goods_code,goods_date,goods_price FROM test_goods_price_change WHERE goods_price IS NOT NULL AND goods_date IS NOT NULL ) AS tmp_b
    		ON tmp_a.goods_code = tmp_b.goods_code AND tmp_a.goods_date > tmp_b.goods_date GROUP BY tmp_a.id
    	) AS tmp_ab 
    	LEFT JOIN (SELECT id,goods_code,goods_date,goods_price FROM test_goods_price_change WHERE goods_price IS NOT NULL AND goods_date IS NOT NULL ) AS tmp_c
    	ON tmp_ab.goods_code = tmp_c.goods_code AND tmp_c.goods_date = tmp_ab.last_date ORDER BY tmp_ab.id
    ) AS tmp
    
    声明 本人博客的所有东西,部分源于网络书籍和视频,其他的是个人的理解感悟,经过自己整理撰写成博客。 本人博客均只用于个人学习、复习,不作为商业用途,如有侵权,请联系我修改或删除。 联系邮箱:itlaowen@163.com
  • 相关阅读:
    __doPostBack的使用
    【转】function,new,constructor and prototye
    谈谈一些网页游戏失败的原因到底有哪些?(转)
    全面剖析页游巨头发家史(转)
    2013.02.20开通博客
    老子喜欢的女人
    如何成为强大的程序员?(转)
    注重健康
    学习方法总结
    数据库知识点滴积累
  • 原文地址:https://www.cnblogs.com/laowenBlog/p/14732305.html
Copyright © 2020-2023  润新知