• hdu-3790-最短路径问题(Dijkstra)


    题目链接

     1 /*
     2     Name:hdu-3790-最短路径问题
     3     Copyright:
     4     Author:
     5     Date: 2018/4/16 19:16:25
     6     Description:
     7     
     8     dijkstra 模板题
     9 */
    10 #include <cstring>
    11 #include <algorithm>
    12 #include <iostream>
    13 using namespace std;
    14 const int MaxN = 1010;
    15 const int INF = 0x3f3f3f3f;
    16 int dis[MaxN], g[MaxN][MaxN],N, src, costEdge[MaxN][MaxN], cost[MaxN];
    17 bool v[MaxN];
    18 
    19 void dijkstra() {
    20     for (int i=1; i<=N; i++){
    21          dis[i] = INF;
    22          cost[i] = INF;
    23     }
    24     dis[src] = 0;
    25     cost[src] = 0;
    26     memset(v, 0, sizeof(v));
    27     for (int i=1; i<=N; i++) {
    28         int mark = -1, mindis = INF;
    29         for (int j=1; j<=N; ++j) {
    30             if (!v[j] && dis[j]<mindis) {
    31                 mindis = dis[j];
    32                 mark = j;
    33             }
    34         }
    35         v[mark] = 1;
    36         for (int j=1; j<=N; ++j) {
    37             if (!v[j]) {
    38                  if (dis[mark] + g[mark][j] < dis[j]) {
    39                     dis[j] = dis[mark] + g[mark][j];
    40                      cost[j] = cost[mark] + costEdge[mark][j];
    41                  } else if(dis[mark] + g[mark][j] == dis[j] && cost[j] > cost[mark] + costEdge[mark][j]) {
    42                      cost[j] = cost[mark] + costEdge[mark][j];
    43                  }
    44             }
    45         }
    46     }
    47 }
    48 int final[MaxN];
    49 int main()
    50 {
    51 //    freopen("in.txt", "r", stdin);
    52     int m;
    53     while (~scanf("%d %d", &N, &m) && (N || m)) {
    54         memset(g, 0x3f, sizeof(g));
    55         memset(dis, 0, sizeof(dis));
    56         memset(cost, 0, sizeof(cost));
    57         memset(costEdge, 0x3f, sizeof(costEdge));
    58 
    59         for (int i=0; i<m; i++) {
    60             int u, v, w, c;
    61             scanf("%d %d %d %d", &u, &v, &w, &c);
    62             if(w < g[u][v]) { //必须判断 重边否则WA 
    63                 g[u][v] = g[v][u] = w;
    64                 costEdge[u][v] = costEdge[v][u] = c;
    65             }
    66         }
    67         int final = 0;
    68         scanf("%d %d", &src, &final);
    69         dijkstra();
    70         printf("%d %d
    ", dis[final], cost[final]);
    71     }
    72     return 0;
    73 }
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  • 原文地址:https://www.cnblogs.com/langyao/p/8858667.html
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