// ConsoleApplication4.cpp : 定义控制台应用程序的入口点。 // #include "stdafx.h" #include<stdio.h> #include<stdlib.h> #include<conio.h> #include<time.h> #include<Windows.h> /********函数变量声明********/ #define PR_Box printf("■") #define PR_Gold printf("★") #define PR_Ag printf("☆") #define PR_FBird printf("Ю") #define PR_DBird printf("Ф") #define PR_Land printf("┳┳┯") #define PR_Bg_TL printf("╔") #define PR_Bg_TR printf("╗") #define PR_Bg_DL printf("╚") #define PR_Bg_DR printf("╝") #define PR_Bg_X printf("═") #define PR_Bg_Y printf("║") #define PR_Blank printf(" "); int Grade = 1, C_Gold = 0, C_Ag = 0, Score = 0, Delay_time = 1000, Max_blank = 9, Distance = 18; //Grade 游戏等级 //Score 分数 //Max_blank 上下两个烟囱之间的最大距离 //Distance 左右两个烟囱之间的距离 struct Birds//小鸟的结构体 { int x, y;//小鸟的位置 int condition;//此变量未用 }; Birds *Bird = (Birds*)malloc(sizeof(Birds));//给小鸟指针分配空间 struct Bg//烟囱的结构体--循环双向链表 { int x, y;//上烟囱的左下角砖块的坐标 int l_blank;//上相两个烟囱之间的距离 int reward[9]; Bg *pri;//前指针-指向前一个结点 Bg *next;//后指针-指向后一个结点 }; Bg *Bg1 = new Bg[sizeof(Bg)];//将一个烟囱结点设置成全局变量 void Position(int x, int y)//将光标移动到X,Y坐标处 { COORD pos = { x - 1, y - 1 }; HANDLE Out = GetStdHandle(STD_OUTPUT_HANDLE); SetConsoleCursorPosition(Out, pos); } void CreatBird()//创建小鸟 { Bird->x = 41;//小鸟的坐标 Bird->y = 10; Bird->condition = 0; } void CreatBg()//创建数据结构为循环双向链表的烟囱 { Bg *Bg2 = (Bg*)malloc(sizeof(Bg)); Bg1->x = 90; Bg1->y = 8; Bg2->x = Bg1->x + Distance; Bg2->y = 9; Bg1->l_blank = Max_blank - Grade; Bg2->l_blank = Max_blank - Grade; Bg1->next = Bg2; Bg1->pri = Bg2; Bg2->next = Bg1; Bg2->pri = Bg1; } void InsertBg(Bg *p)//创建一个结点插入到传入结点之前。循环双向链表的插入 { int temp; Bg *Bgs = (Bg*)malloc(sizeof(Bg)); Bgs->x = p->pri->x + Distance; Bgs->l_blank = Max_blank - Grade; srand((int)time(0));//将系统时间作为产生随机数的种子 temp = rand();//产生随机数 if (temp % 2 == 0)//当随机数%==2时，烟囱口向下移动 { if ((temp % 4 + p->pri->y + Max_blank - Grade)<21)//检测是否存在向下移动的可行性 Bgs->y = p->pri->y + temp % 4;//若有则向下移动temp%4个单位 else Bgs->y = p->pri->y;//若无，则不动 } else//反之亦然 { if ((p->pri->y - temp % 4)>2) Bgs->y = p->pri->y - temp % 4; else Bgs->y = p->pri->y; } Bgs->pri = p->pri;//循环链表指向 Bgs->next = p; p->pri->next = Bgs; p->pri = Bgs; } void Check_Bg(Bg *q)//检查是否有烟囱超出屏幕，若有超出，则移动到屏幕右侧。 { Bg *p = q; int i = 0, temp; while (++i <= 5)//注意烟囱只有5个，时来回循环移动的 { if (p->x>-4)//若有烟囱超出 p = p->next; else { srand((int)time(0)); temp = rand(); if (temp % 2 == 0)//++ { if ((temp % 4 + p->y + Max_blank - Grade)<21) p->y = p->y + temp % 4; else p->y = p->y; p->x = p->pri->x + Distance;//将烟囱移动到前一结点的右侧+Distance的单位 p->l_blank = Max_blank - Grade;//计算上下两个烟囱的距离 } else//反之亦然 { if ((p->y - temp % 4)>2) p->y = p->y - temp % 4; else p->y = p->y; p->x = p->pri->x + Distance; p->l_blank = Max_blank - Grade; } } } } void Loop_Bg(Bg *q)//烟囱单向循环移动 { Bg *p = q; int i = 0; while (++i <= 5) { p->x = p->x - 1; p = p->next; if (Bird->x == p->x)//每经过一个烟囱，加一分 { Score += 1; if (Score % 4 == 0 && Grade<4)//烟囱 Grade++; } } } void Prt_Bg(Bg *q)//画烟囱----较冗余的代码 { Bg *p = q; int i = 0, k, j; while (++i <= 5) { if (p->x>0 && p->x <= 78) { for (k = 2; k<p->y; k++)//画出上烟囱上半部分 { Position(p->x + 1, k); PR_Box; PR_Box; PR_Blank;//输出两个格子，输出空格，清除原来余影 } Position(p->x, p->y);//画出上烟囱下半部分 PR_Box; PR_Box; PR_Box; PR_Blank;//输出三个格子，输出空格，清除原来余影 Position(p->x, p->y + p->l_blank);//画出下烟囱上半部分 PR_Box; PR_Box; PR_Box; PR_Blank;//输出三个格子，输出空格，清除原来余影 k = k + p->l_blank + 1; for (k; k <= 22; k++)//画出下烟囱下半部分 { Position(p->x + 1, k); PR_Box; PR_Box; PR_Blank;//输出两个格子，输出空格，清除原来余影 } Position(p->x, 23);//输出地下的线 for (k = 1; k<Distance / 3 - 2; k++) PR_Land; } p = p->next; if (p->x == 0) { for (j = 2; j<p->y; j++) { Position(p->x + 1, j); PR_Blank; PR_Blank; } Position(p->x + 1, p->y); PR_Blank; PR_Blank; PR_Blank; Position(p->x + 1, p->y + Max_blank - Grade); PR_Blank; PR_Blank; PR_Blank; j = j + Max_blank - Grade + 1; for (j; j <= 22; j++) { Position(p->x + 1, j); PR_Blank; PR_Blank; } } } } void PrtBg()//画上下两条线 { int i; Position(1, 1); PR_Bg_TL; Position(79, 1); PR_Bg_TR; Position(1, 24); PR_Bg_DL; Position(79, 24); PR_Bg_DR; for (i = 3; i <= 78; i += 2) { Position(i, 1); PR_Bg_X; Position(i, 24); PR_Bg_X; } /*for(i=2;i<=23;i++) { Position(1,i);PR_Bg_Y;printf("%d",i-1); Position(79,i);PR_Bg_Y; }*/ } void PrtBird()//画鸟 { Position(Bird->x, Bird->y - 1);//清除原来屏幕上面的鸟 PR_Blank; Position(Bird->x, Bird->y);//画新鸟 PR_FBird; Position(38, 2); printf("Score:%d", Score);//输出得分 } int CheckYN(Bg *q)//检查是否撞壁 { Bg *p = q; int i = 0; while (++i <= 5) { if (Bird->y>23)//鸟是否落地 return 0; if (Bird->x == p->x&&Bird->y <= p->y)//是否撞到上烟囱左侧 return 0; if ((Bird->x == p->x || Bird->x == p->x + 1 || Bird->x == p->x + 2) && Bird->y == p->y)//是否撞到上烟囱下侧 return 0; if (Bird->x == p->x&&Bird->y>p->y + p->l_blank)//是否撞到下烟囱左侧 return 0; if ((Bird->x == p->x || Bird->x == p->x + 1 || Bird->x == p->x + 2) && Bird->y == p->y + p->l_blank)//是否撞到上烟囱上侧 return 0; p = p->next; } return 1; } void Prtfirst() { printf("══════════════════════════════════════ "); printf(" ■■ ■■ "); printf(" ■■ ■■ "); printf(" ■■ ■■ C语言版 Flappy Bird "); printf(" ■■ ■■ 瞎搞人：yyposs "); printf(" ■■ ■■ 瞎搞日期：2014.2 "); printf(" ■■ ■■ 耗时：4小时 "); printf(" ■■■ ■■ 游戏说明： "); printf(" ■■ 1-按上箭头使鸟起飞 "); printf(" ■■ 2-等级越高，难度越大！ "); printf(" Ю ■■■ "); printf(" "); printf(" ■■■ 欢迎各路大神与我探讨C、C++、VB、PHP、C# "); printf(" ■■ "); printf(" ■■ "); printf(" ■■ ■■■ 【无版权，随意修改】 "); printf(" ■■ ■■ "); printf(" ■■ Ф ■■ "); printf(" ■■ ■■ "); printf(" ■■ ■■ "); printf(" ■■ ■■ "); printf(" ■■ ■■ "); printf(" ┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳ "); system("pause"); Position(1, 1); int i = 0; while (i++<40 * 25) PR_Blank; } void main() { int i = 0; char ch; Prtfirst();//开始屏幕 PrtBg();//画上下两边的框框 CreatBg();//创建循环双向链表烟囱 InsertBg(Bg1);//给循环双向链表中插入一个烟囱结点 InsertBg(Bg1);//给循环双向链表中插入一个烟囱结点 InsertBg(Bg1);//给循环双向链表中插入一个烟囱结点 CreatBird();//创造小鸟 while (1) { if (!CheckYN(Bg1))//检查鸟是否碰壁 break;//若碰壁，则退出 Check_Bg(Bg1);//检查是否有烟囱X坐标<0 Prt_Bg(Bg1);//画背景烟囱 PrtBird();//画小鸟 Loop_Bg(Bg1);//背景烟囱单项循环 Bird->y = Bird->y + 1; if (GetAsyncKeyState(VK_UP))//检测是否有按键 { Position(Bird->x, Bird->y - 1); PR_Blank;//在屏幕上清除原小鸟 Bird->y = Bird->y - 4;//鸟的位置上升4个长度 } while (i++<500); { Sleep(100); } i = 0; } Position(38, 10); printf("You Lost!"); Position(1, 25); system("pause"); } // 1 2 3 4 5 6 7 8 10 15 20 25 30 35 38 //══════════════════════════════════════ //1 ■■ ■■ //2 ■■ ■■ //3 ■■ ■■ //4 ■■ ■■ //5 ■■ ■■ //6 ■■ ■■ //7 ■■■ ■■ //8 ■■ //9 ■■ //10 Ю ■■■ //11 //12 ■■■ //13 ■■ //14 ■■ //15 ■■ ■■■ //16 ■■ ■■ //17 ■■ Ф ■■ //18 ■■ ■■ //19 ■■ ■■ //20 ■■ ■■ //21 ■■ ■■ //22┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳┳┯┳ //══════════════════════════════════════