• 机器人走迷宫(dfs)


    http://acm.sdut.edu.cn/sdutoj/problem.php?action=showproblem&problemid=1590

     1 #include <stdio.h>
     2 #include <string.h>
     3 int n,m,s_x,s_y,e_x,e_y;
     4 char map[15][15];
     5 
     6 int Deal(char c)
     7 {
     8     if(c=='R'&&map[s_x][s_y+1]!='#')
     9     {
    10         s_y++;
    11         if (s_x==e_x&&s_y==e_y)
    12             return 1;
    13     }
    14     else if(c=='L'&&map[s_x][s_y-1]!='#')
    15     {
    16         s_y--;
    17         if (s_x==e_x&&s_y==e_y)
    18             return 1;
    19     }
    20     else if(c=='U'&&map[s_x-1][s_y]!='#')
    21     {
    22         s_x--;
    23         if (s_x==e_x&&s_y==e_y)
    24             return 1;
    25     }
    26     else if(c=='D'&&map[s_x+1][s_y]!='#')
    27     {
    28         s_x++;
    29         if (s_x==e_x&&s_y==e_y)
    30             return 1;
    31     }
    32     return 0;
    33 }
    34 int main()
    35 {
    36     char str[120],s[15][15];
    37     scanf("%d %d",&n,&m);
    38     memset(map,'#',sizeof(s));//初始化全为墙
    39     for (int i = 0; i < n; i ++)
    40     {
    41         scanf("%s",s[i]);
    42         for (int j = 0; j < m; j ++)
    43         {
    44 
    45             if (s[i][j]=='S')
    46             {
    47                 s_x = i+1;
    48                 s_y = j+1;
    49             }
    50             if (s[i][j]=='T')
    51             {
    52                 e_x = i+1;
    53                 e_y = j+1;
    54             }
    55             map[i+1][j+1] = s[i][j];//给图像周围增加一堵墙,防止出界
    56 
    57         }
    58     }
    59 
    60     int ans = 0,k;
    61     scanf("%d",&k);
    62     scanf("%s",str);
    63     for (int i =  0; i < k; i ++)
    64     {
    65         ans = Deal(str[i]);
    66         if (ans)
    67             break;
    68     }
    69     if (ans)
    70         puts("Yes");
    71     else
    72         puts("No");
    73     return 0;
    74 }
    View Code
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  • 原文地址:https://www.cnblogs.com/lahblogs/p/3365545.html
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