Given a binary tree, check whether it is a mirror of itself (ie, symmetric around its center).
For example, this binary tree is symmetric:
1 / 2 2 / / 3 4 4 3
But the following is not:
1 / 2 2 3 3
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public boolean isSymmetric(TreeNode root) { return isSymmetric(root,root); } public boolean isSymmetric(TreeNode t1,TreeNode t2) { if(t1==null && t2==null) return true; if(t1==null || t2==null) return false; return(t1.val==t2.val && isSymmetric(t1.left,t2.right) && isSymmetric(t1.right,t2.left)); } }