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今天下午写两个函数,还是比较通用的~~~
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/**//// <summary>
/// 产生由英文和数字组成的指定个数的随机数
/// </summary>
/// <param name="number">产生随机数的个数</param>
/// <returns>指定个数的随机英数字符串</returns>
public static string GetRandomCode(int number)
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{
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string[] arrList = new string[]
{"0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F","G",
"H","I","J","K","L","M","N","O","P","Q","R","S","T","U","W","X","Y","Z"} ;
StringBuilder sb = new StringBuilder("") ;
Random random = new Random() ;
for( int i = 0 ; i < number ; i++ )
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{
sb.Append(arrList[(int)random.Next(0,arrList.Length)]) ;
}
return sb.ToString() ;
}
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/**//// <summary>
/// 判断号码是联通,移动,电信中的哪个,在使用本方法前,请先验证号码的合法性
/// 规则:前三位为130-133 联通 ;前三位为135-139或前四位为1340-1348 移动; 其它的应该为电信
/// </summary>
/// <param name="mobile">要判断的号码</param>
/// <returns>返回相应类型:1代表联通;2代表移动;3代表电信</returns>
public static int GetMobileType(string mobile)
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{
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string[] chinaUnicom = new string[]
{"130","131","132","133"} ;
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string[] chinaMobile1 = new string[]
{"135","136","137","138","139"} ;
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string[] chinaMobile2 = new string[]
{"1340","1341","1342","1343","1344","1345","1346","1347","1348"} ;
bool bolChinaUnicom = (Array.IndexOf(chinaUnicom,mobile.Substring(0,3)) >= 0) ;
bool bolChinaMobile1 = (Array.IndexOf(chinaMobile1,mobile.Substring(0,3)) >=0) ;
bool bolChinaMobile2 = (Array.IndexOf(chinaMobile2,mobile.Substring(0,4)) >=0) ;
if (bolChinaUnicom)
return 1 ;//联通
if ( bolChinaMobile1 || bolChinaMobile2 )
return 2 ; //移动
return 3 ; //其他为电信
}
注:有朋友建议,第二方法用正则表达式实现更好,确实不错,下面把第二方法的新实现贴上:
![](/Images/OutliningIndicators/ExpandedBlockStart.gif)
/**//// <summary>
/// 判断号码是联通,移动,电信中的哪个,在使用本方法前,请先验证号码的合法性
/// 规则:前三位为130-133 联通 ;前三位为135-139或前四位为1340-1348 移动; 其它的应该为电信
/// </summary>
/// <param name="mobile">要判断的号码</param>
/// <returns>返回相应类型:1代表联通;2代表移动;3代表电信</returns>
public static int GetMobileType(string mobile)
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{
if (IsChinaUnicomNumber(mobile))
return 1 ;
if (IsChinaMobileNumber(mobile))
return 2 ;
return 3 ;
}
//是否是联通的号码 测试通过
private static bool IsChinaUnicomNumber(string mobile)
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{
string sPattern = "^(130|131|132|133)[0-9]{8}";
bool isChinaUnicom = Regex.IsMatch(mobile,sPattern) ;
return isChinaUnicom ;
}
//是否是移动的号码 测试通过
private static bool IsChinaMobileNumber(string mobile)
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{
string sPattern = "^(135|136|137|138|139|1340|1341|1342|1343|1344|1345|1346|1347|1348)[1-9]{7,8}" ;
return Regex.IsMatch(mobile,sPattern) ;
}
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原文地址:https://www.cnblogs.com/kwklover/p/83081.html
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