• mysql 基本操作练习


     1 create table employee (name varchar(30), sex char(2), age int, address varchar(30));
     2 
     3 insert into employee values ('张三', '', 19, '北京');
     4 insert into employee values ('李四', '', 20, '上海');
     5 insert into employee values ('王五', '', 25, '广州');
     6 insert into employee values ('薛六', '', 20, '北京');
     7 insert into employee values ('王五', '', 22, '北京');
     8 insert into employee values ('赵七', '', 28, '上海');
     9 insert into employee values ('张四', '', 23, '北京');
    10 
    11 #(1). 写出sql语句,查询所有年龄大于20岁的员工(2分)
    12 select *from employee where age>20;
    13 #(2). 写出sql语句,查询所有年龄小于25岁的女性员工(3分)
    14 select *from employee where sex='' and age<25;
    15 #(3). 写出sql语句,统计男女员工各有多少名(3分)
    16 #count 函数 
    17 select count(*) from employee;#统计表元素个数
    18 select count(*) from employee where sex='';#统计女生个数
    19 select sex,count(*) from employee group by sex;#group by sex 按性别分组,用性别标记分组
    20 select sex,count(*) as num from employee group by sex;#as 起别名
    21 
    22 #(4). 写出sql语句,按照年龄倒序获取员工信息(3分)
    23 select * from employee order by age desc;
    24 #(5). 写出sql语句,获取员工中哪个姓名具有重名现象(3分)
    25 SELECT *  
    26   FROM employee  
    27  WHERE name IN (SELECT name  
    28                   FROM employee  
    29                  GROUP BY name  
    30                 HAVING COUNT(*) > 1)  
    31 #(6). 写出sql语句,查询所有姓张的员工(3分)
    32 select * from employee where name like '%张%';#模糊查询,只要含张字
    33 select * from employee where name like '张%';#只要姓张
    34 #占位符写法
    35 select * from employee where name like '张__';
    36 #(7). 写出sql语句,查询住址为北京的前3条记录(3分)
    37 select * from employee where address='北京'  order by name asc limit 0,3;#从下标几开始 ,几个
    38 select * from employee limit 3,3;
    39 #(8). 写出sql语句,查询员工总数(3分)
    40 select count(*) as allnum from employee;
    41 #(9). 写出sql语句,向表中插入一条记录(2分)
    42 insert into employee(name,sex,age,address) values('七七','',20,'深圳');
    43 #(10).写出sql语句,修改员工张四的住址为南京(2分)
    44 update employee set address='南京' where name='张四';
    45 #(11).写出sql语句,删除年龄大于24岁的女员工(2分)
    46 delete from employee where age>24 and sex='';
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  • 原文地址:https://www.cnblogs.com/kimsimple/p/5697247.html
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