JavaScript将数组变成*

Description:

Write a function that accepts an array of 10 integers (between 0 and 9), that returns a string of those numbers in the form of a phone number.

Example:

createPhoneNumber([1, 2, 3, 4, 5, 6, 7, 8, 9, 0]) // => returns "(123) 456-7890"

my answer：使用正则表达式

function createPhoneNumber(numbers){
   var pattern = /(d{3})(d{3})(d{4})/
   pattern.test(numbers.join(''));
   return '('+ RegExp.$1 +')'+ ' ' + RegExp.$2 +'-'+RegExp.$3;
}

console.log(createPhoneNumber([1, 2, 3, 4, 5, 6, 7, 8, 9, 0]));

best answer：

function createPhoneNumber(numbers){
  return numbers.join('').replace(/(...)(...)(.*)/, '($1) $2-$3');
}

other answer ：不使用正则

function createPhoneNumber(numbers){
  var format = "(xxx) xxx-xxxx";  
  for(var i = 0; i < numbers.length; i++)
  {
    format = format.replace('x', numbers[i]);
  }  
  return format;
}