打表+二分
#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
const LL inf=1e18+100;
LL a[20000];
int num;
void init()
{
num=0;
LL i,j,z;
for(i=1;i<inf;i=i*2){
for(j=1;j*i<inf;j=j*3){
for(z=1;i*j*z<inf;z=z*5){
a[num++]=i*j*z;
}
}
}
sort(a+1,a+num);
}
int main()
{
init();
int T;
scanf("%d",&T);
while(T--)
{
LL n;
scanf("%lld",&n);
int left=1,right=num-1;
while(left<right)
{
int mid=left+(right-left)/2;
if(a[mid]>=n)
right=mid;
else
left=mid+1;
}
printf("%lld
",a[left]);
}
return 0;
}