• HDOJ 2871 Memory Control(线段树区间合并与查询)


    思路:

    hotel的加强版。把申请到的内存都放到vector容器里面,然后再利用STL里面的upper_bound函数操作即可。写完之后感觉很爽。

    #include <cstdio>
    #include <algorithm>
    #include <vector>
    using namespace std;
    
    #define lhs l, m, rt << 1
    #define rhs m + 1, r, rt << 1 | 1
    
    const int maxn = 50010;
    int sum[maxn << 2], lsum[maxn << 2], rsum[maxn << 2];
    int lab[maxn << 2];
    
    enum __op { __free = 0, __new };
    
    typedef struct _node {
        int beg, end;
        _node(int _b, int _e) : beg(_b), end(_e) { };
        friend bool operator < (const _node& n1, const _node& n2) { return n1.beg < n2.beg; };
    } node ;
    
    void PushUp(int l, int r, int rt)
    {
        lsum[rt] = lsum[rt << 1];
        rsum[rt] = rsum[rt << 1 | 1];
    
        int m = (l + r) >> 1;
        if (lsum[rt] == m - l + 1)
            lsum[rt] += lsum[rt << 1 | 1];
        if (rsum[rt] == r - m)
            rsum[rt] += rsum[rt << 1];
    
        sum[rt] = max(sum[rt << 1], sum[rt << 1 | 1]);
        sum[rt] = max(rsum[rt << 1] + lsum[rt << 1 | 1], sum[rt]);
    }
    
    void PushDown(int l, int r, int rt)
    {
        if (lab[rt] != -1)
        {
            int m = (l + r) >> 1;
            lab[rt << 1] = lab[rt << 1 | 1] = lab[rt];
            sum[rt << 1] = lsum[rt << 1] = rsum[rt << 1] = lab[rt] ? 0 : m - l + 1;
            sum[rt << 1 | 1] = lsum[rt << 1 | 1] = rsum[rt << 1 | 1] = lab[rt] ? 0 : r - m;
            lab[rt] = -1;
        }
    }
    
    int Query(int size, int l, int r, int rt)
    {
        if (l == r)
            return r;
    
        int m = (l + r) >> 1;
        PushDown(l, r, rt);
    
        if (sum[rt << 1] >= size)
            return Query(size, lhs);
        else if (rsum[rt << 1] + lsum[rt << 1 | 1] >= size)
            return m - rsum[rt << 1] + 1;
        else 
            return Query(size, rhs);
    
        // PushUp(l, r, rt);
    }
    
    void Update(int beg, int end, __op op, int l, int r, int rt)
    {
        if (beg <= l && r <= end)
        {
            sum[rt] = lsum[rt] = rsum[rt] = op ? 0 : r - l + 1;
            lab[rt] = op;
            return ;
        }
        PushDown(l, r, rt);
    
        int m = (l + r) >> 1;
        if (beg <= m)
            Update(beg, end, op, lhs);
        if (end > m)
            Update(beg, end, op, rhs);
    
        PushUp(l, r, rt);
    }
    
    void Build(int l, int r, int rt)
    {
        sum[rt] = r - l + 1;
        lsum[rt] = rsum[rt] = r - l + 1;
        lab[rt] = -1;
    
        if (l == r)
            return ;
    
        int m = (l + r) >> 1;
        Build(lhs), Build(rhs);
    }
    
    int main()
    {
        int n, m;
        vector<node> mblk;
    
        while (~scanf("%d %d", &n, &m))
        {
            Build(1, n, 1);
    
            mblk.clear();
            for (int i = 0; i < m; ++i)
            {
                char op[16]; 
                scanf("%s", op);
    
                if (op[0] == 'N')
                {
                    int x;
                    scanf("%d", &x);
                    if (sum[1] >= x)
                    {
                        int p = Query(x, 1, n, 1);
                        vector<node>::iterator iter;
    
                        Update(p, p + x - 1, __new, 1, n, 1);
                        printf("New at %d\n", p);
    
                        iter = upper_bound(mblk.begin(), mblk.end(), node(p, p + x - 1));
                        mblk.insert(iter, node(p, p + x - 1));
                    }
                    else
                        printf("Reject New\n");
                }
                else if (op[0] == 'F')
                {
                    int x;
                    scanf("%d", &x);
                    int p = upper_bound(mblk.begin(), mblk.end(), node(x, x)) - mblk.begin() - 1;
    
                    if (p == -1 || mblk[p].end < x)
                        printf("Reject Free\n");
                    else
                    {
                        printf("Free from %d to %d\n", mblk[p].beg, mblk[p].end);
                        Update(mblk[p].beg, mblk[p].end, __free, 1, n, 1);
                        mblk.erase(mblk.begin() + p);
                    }
                }
                else if (op[0] == 'G')
                {
                    int x;
                    scanf("%d", &x);
                    if (x <= mblk.size())
                        printf("Get at %d\n", mblk[x-1].beg);
                    else
                        printf("Reject Get\n");
                }
                else if (op[0] == 'R')
                {
                    Update(1, n, __free, 1, n, 1);
                    // Build(1, n, 1);
                    mblk.clear();
                    printf("Reset Now\n");
                }
            }
            printf("\n");
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/kedebug/p/2868838.html
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