• PAT 甲级 1154 Vertex Coloring (25分)


    A proper vertex coloring is a labeling of the graph's vertices with colors such that no two vertices sharing the same edge have the same color. A coloring using at most k colors is called a (proper) k-coloring.

    Now you are supposed to tell if a given coloring is a proper k-coloring.

    Input Specification:

    Each input file contains one test case. For each case, the first line gives two positive integers N and M (both no more than 10000), being the total numbers of vertices and edges, respectively. Then M lines follow, each describes an edge by giving the indices (from 0 to N1) of the two ends of the edge.

    After the graph, a positive integer K (≤ 100) is given, which is the number of colorings you are supposed to check. Then K lines follow, each contains N colors which are represented by non-negative integers in the range of int. The i-th color is the color of the i-th vertex.

    Output Specification:

    For each coloring, print in a line k-coloring if it is a proper k-coloring for some positive k, or No if not.

    Sample Input:

    10 11
    8 7
    6 8
    4 5
    8 4
    8 1
    1 2
    1 4
    9 8
    9 1
    1 0
    2 4
    4
    0 1 0 1 4 1 0 1 3 0
    0 1 0 1 4 1 0 1 0 0
    8 1 0 1 4 1 0 5 3 0
    1 2 3 4 5 6 7 8 8 9

    Sample Output:

    4-coloring
    No
    6-coloring
    No

    【AC】三部曲:1、[读懂题意]    2、[ pair存边 ]   3、[ set去重 ]

     1 #include<bits/stdc++.h>
     2 using namespace std;
     3 
     4 pair<int, int> p[10001];
     5 
     6 int main()
     7 {
     8     int n, m; cin >> n >> m;
     9     for(int i = 0; i < m; i++)
    10     {
    11         cin >> p[i].first >> p[i].second;
    12     }
    13     
    14     int k, array[10001]; cin >> k;
    15     while(k--)
    16     {
    17         set<int> s; int flag = 1;
    18         for(int i = 0; i < n; i++)
    19         {
    20             cin >> array[i];
    21             s.insert(array[i]);
    22         }
    23         for(int i = 0; i < m; i++)
    24         {
    25             if(array[p[i].first] == array[p[i].second]) { cout << "No" << endl; flag = 0; break; }
    26         }
    27         if(flag) cout << s.size() << "-coloring" << endl;
    28         s.clear();
    29     }
    30     return 0;
    31 }
    View Code

    "只要你不停止,走慢一点没关系"

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  • 原文地址:https://www.cnblogs.com/kamisamalz/p/13495489.html
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