1、div的水平太难了，加上clean code看多了，写的太长了，凑活着看吧....
1 #include <iostream> 2 #include <string> 3 #include <vector> 4 #include <cstdlib> 5 #include <cmath> 6 #include <map> 7 #include <stack> 8 #include <algorithm> 9 #include <list> 10 #include <ctime> 11 #include <set> 12 #include <queue> 13 typedef long long ll; 14 using namespace std; 15 #define CLR(arr, what) memset(arr, what, sizeof(arr)) 16 class UndoHistory { 17 public: 18 void addone(map<string, int>& allstate, string& var) { 19 allstate[var] = 1; 20 } 21 bool checkexist(map<string, int>& allstate, string& var) { 22 if (allstate[var] == 1) { 23 return true; 24 } 25 return false; 26 } 27 int checklong(map<string, int>& allstate, string& target){ 28 int sz=target.size(); 29 int i; 30 bool judge; 31 string cur; 32 int res=0; 33 for(i=0;i<sz;i++){ 34 cur=target.substr(0,i+1); 35 judge=checkexist(allstate,cur); 36 if(judge){ 37 res=i+1; 38 } 39 } 40 return res; 41 } 42 bool checkpre(string& pre,string& cur){ 43 int szpre=pre.size(); 44 int szcur=cur.size(); 45 if(szcur<szpre){ 46 return false; 47 } 48 for(int i=0;i<szpre;i++){ 49 if(pre[i]!=cur[i]){ 50 return false; 51 } 52 } 53 return true; 54 } 55 int minPresses(vector<string> lines) { 56 map<string, int> allstate; 57 string tmp; 58 int sz = (lines[0]).size(); 59 for (int i = 0; i < sz; i++) { 60 tmp = (lines[0]).substr(0, i + 1); 61 addone(allstate, tmp); 62 } 63 int res=sz+1; 64 sz=lines.size(); 65 66 for(int i=1;i<sz;i++){ 67 int szpre=lines[i-1].size(); 68 int szcur=lines[i].size(); 69 int his=checklong(allstate,lines[i]); 70 bool judge=checkpre(lines[i-1],lines[i]); 71 int b=szcur-his+2+1; 72 if(judge){ 73 int a=szcur-szpre+1; 74 res=res+min(a,b); 75 }else{ 76 res=res+b; 77 } 78 for(int j=0;j<szcur;j++){ 79 tmp=(lines[i]).substr(0,j+1); 80 addone(allstate,tmp); 81 } 82 } 83 return res; 84 85 } 86 };
2、其实就是状态压缩啊，petr的代码很给力啊~~~
1 #include <iostream> 2 #include <string> 3 #include <vector> 4 #include <cstdlib> 5 #include <cmath> 6 #include <map> 7 #include <algorithm> 8 #include <list> 9 #include <ctime> 10 #include <string.h> 11 #include <queue> 12 #include <sstream> 13 using namespace std; 14 const int INF = 99999999; 15 class TravellingPurchasingMan { 16 public: 17 int OneCount(unsigned int x) { 18 int count; 19 for (count = 0; x > 0; count++) 20 x &= x - 1; //把最后面的1变0 21 return count; 22 } 23 int maxStores(int N, vector<string> interestingStores, 24 vector<string> roads) { 25 vector<vector<int> > dist(N, vector<int>(N, INF)); 26 for (int i = 0; i < N; ++i) { 27 dist[i][i] = 0; 28 } 29 stringstream ssvar; 30 int sz = interestingStores.size(); 31 int sz2 = roads.size(); 32 for (int i = 0; i < sz2; i++) { 33 ssvar.clear(); 34 ssvar << roads[i]; 35 int a, b, c; 36 ssvar >> a >> b >> c; 37 dist[a][b] = min(dist[a][b], c); 38 dist[b][a] = min(dist[b][a], c); 39 } 40 for (int k = 0; k < N; ++k) 41 for (int i = 0; i < N; ++i) 42 for (int j = 0; j < N; ++j) 43 dist[i][j] = min(dist[i][j], dist[i][k] + dist[k][j]); 44 vector<int> open(sz, 0); 45 vector<int> close(sz, 0); 46 vector<int> duration(sz, 0); 47 48 for (int i = 0; i < sz; ++i) { 49 ssvar.clear(); 50 ssvar << interestingStores[i]; 51 int a, b, c; 52 ssvar >> a >> b >> c; 53 open[i] = a; 54 close[i] = b; 55 duration[i] = c; 56 } 57 vector<vector<int> > best(sz, vector<int>(1 << sz, INF)); 58 59 best[0][0] = 0; 60 int res = 0; 61 for (int set = 0; set < (1 << sz); ++set) { 62 int bits = OneCount(set); 63 for (int last = 0; last < sz; ++last) { 64 int earliest = best[last][set]; 65 if (earliest >= INF) 66 continue; 67 res = max(res, bits); 68 int curPos = last; 69 if (set == 0) 70 curPos = N - 1; 71 for (int dest = 0; dest < sz; ++dest) { 72 if ((set & (1 << dest)) == 0) {//没有去过 73 int toGet = earliest + dist[curPos][dest]; 74 if (toGet > close[dest])//到达时间晚了 75 continue; 76 if (toGet < open[dest]) 77 toGet = open[dest]; 78 toGet += duration[dest]; 79 if (toGet < best[dest][set ^ (1 << dest)]) { 80 best[dest][set ^ (1 << dest)] = toGet; 81 } 82 } 83 } 84 } 85 } 86 return res; 87 } 88 };