• PS 滤镜——素描算法(二)


    利用第二种算法完毕素描特效的生成。


    %%% Sketch
    clc;
    clear all;
    Image=imread('4.jpg');
    Image=double(Image);
    [row,col,layer]=size(Image);

    Filter_size=30;
    sigma=Filter_size/6;
    F_gaussian=fspecial('gaussian', Filter_size, sigma);

    for i=1:row
        for j=1:col
            I(i,j)=max(Image(i,j));
        end
    end
    I=I/255;
    p=1;
    Gradient_X=[-1 -p -1
                0   0  0
                1   p  1];
            
    Gradient_Y=[-1 0 1
                -p 0 p
                -1 0 1];
    Image_y=imfilter(I, Gradient_Y, 'conv');        
    Image_x=imfilter(I, Gradient_X, 'conv');

    alpha=0.5;
    % Image_edge=(abs(Image_x)*alpha+(1-alpha)*abs(Image_y));
    Image_edge=(abs(Image_x)+abs(Image_y));

    F_image=imfilter(Image,F_gaussian,'conv');
    [L,a,b]=Rgb2Lab(F_image);
    I=sqrt(L.*L+a.*a+b.*b);
    I_mean=mean(mean(I));
    F_S=I;
    for i=1:row
        for j=1:col
            if(I(i,j)<I_mean)
                F_S(i,j)=(1-I(i,j)/I_mean).^2;
            else
                F_S(i,j)=0;
            end
        end
    end

    Image_out=(1-Image_edge).*(0.8-F_S);

    %% 设置底色层
        Image_Dodge(:,:,1)=Image_out;
        Image_Dodge(:,:,2)=Image_out;
        Image_Dodge(:,:,3)=Image_out;
        Base_layer=Image_out;
        Base_layer(:,:,1)=210/255;
        Base_layer(:,:,2)=225/255;
        Base_layer(:,:,3)=105/255;
       alpha=0.7;
       Image1=alpha*Image_Dodge+(1-alpha)*Base_layer;
       Image3=Image_Dodge.*Image1;
       figure, imshow(Image3);
     

    %%%  Rgb2Lab
    %%%  
    function [L,a,b]=Rgb2Lab(Image)
    Image=double(Image)/255;
    R=Image(:,:,1);
    G=Image(:,:,2);
    B=Image(:,:,3);

    X=0.5767309*R + 0.1855540*G + 0.1881852*B;
    Y=0.2973769*R + 0.6273491*G + 0.0752741*B;
    Z=0.0270343*R + 0.0706872*G + 0.9911085*B;
    [row, col]=size(R);

    L=R;
    a=R;
    b=R;

    for i=1:row
        for j=1:col        
            L(i,j)=116*F_Correction(Y(i,j))-16;
            a(i,j)=500*(F_Correction(X(i,j))-F_Correction(Y(i,j)));
            b(i,j)=200*(F_Correction(Y(i,j))-F_Correction(Z(i,j)));
        end
    end



     原图


     效果图


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  • 原文地址:https://www.cnblogs.com/jzssuanfa/p/7234645.html
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