• bzoj1486【HNOI2009】最小圈


    1486: [HNOI2009]最小圈

    Time Limit: 10 Sec  Memory Limit: 64 MB
    Submit: 1778  Solved: 827
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    Description

    Input

    Output

    Sample Input

    Sample Output

    HINT

    Source




    01分数规划+二分答案+spfa判负环




    #include<iostream>
    #include<cstdio>
    #include<cmath>
    #include<cstring>
    #include<cstdlib>
    #include<algorithm>
    #define F(i,j,n) for(int i=j;i<=n;i++)
    #define D(i,j,n) for(int i=j;i>=n;i--)
    #define ll long long
    #define maxn 3005
    #define maxm 10005
    #define inf 1000000000
    #define eps 1e-9
    using namespace std;
    struct edge{int next,to;double v,w;}e[maxm];
    int n,m,cnt,head[maxn];
    double dis[maxn];
    bool flag,mark[maxn];
    inline int read()
    {
    	int x=0,f=1;char ch=getchar();
    	while (ch<'0'||ch>'9'){if (ch=='-') f=-1;ch=getchar();}
    	while (ch>='0'&&ch<='9'){x=x*10+ch-'0';ch=getchar();}
    	return x*f;
    }
    inline void add_edge(int x,int y)
    {
    	e[++cnt].next=head[x];
    	e[cnt].to=y;
    	head[x]=cnt;
    }
    inline void spfa(int x)
    {
    	if (mark[x]){flag=true;return;}
    	mark[x]=true;
    	for(int i=head[x],y;i;i=e[i].next)
    		if (dis[x]+e[i].v<dis[y=e[i].to])
    		{
    			dis[y]=dis[x]+e[i].v;
    			spfa(y);
    			if (flag) return;
    		}
    	mark[x]=false;
    }
    inline bool judge()
    {
    	F(i,1,n) dis[i]=mark[i]=0;
    	flag=false;
    	F(i,1,n)
    	{
    		spfa(i);
    		if (flag) return true;
    	}
    	return false;
    }
    int main()
    {
    	n=read();m=read();
    	int x,y;double z,l=inf,r=-inf,mid;
    	F(i,1,m)
    	{
    		x=read();y=read();scanf("%lf",&z);
    		add_edge(x,y);
    		e[i].w=z;
    		l=min(l,z);
    		r=max(r,z);
    	}
    	while (r-l>=eps)
    	{
    		mid=(l+r)/2;
    		F(i,1,m) e[i].v=e[i].w-mid;
    		if (judge()) r=mid;
    		else l=mid;
    	}
    	printf("%.8lf
    ",l);
    	return 0;
    }
    


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  • 原文地址:https://www.cnblogs.com/jzssuanfa/p/7224902.html
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