Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 10428 | Accepted: 3959 |
Description
WFF 'N PROOF is a logic game played with dice. Each die has six faces representing some subset of the possible symbols K, A, N, C, E, p, q, r, s, t. A Well-formed formula (WFF) is any string of these symbols obeying the following rules:
- p, q, r, s, and t are WFFs
- if w is a WFF, Nw is a WFF
- if w and x are WFFs, Kwx, Awx, Cwx, and Ewx are WFFs.
- p, q, r, s, and t are logical variables that may take on the value 0 (false) or 1 (true).
- K, A, N, C, E mean and, or, not, implies, and equals as defined in the truth table below.
|
w x | Kwx | Awx | Nw | Cwx | Ewx |
1 1 | 1 | 1 | 0 | 1 | 1 |
1 0 | 0 | 1 | 0 | 0 | 0 |
0 1 | 0 | 1 | 1 | 1 | 0 |
0 0 | 0 | 0 | 1 | 1 | 1 |
A tautology is a WFF that has value 1 (true) regardless of the values of its variables. For example, ApNp is a tautology because it is true regardless of the value of p. On the other hand, ApNq is not, because it has the value 0 for p=0, q=1.
You must determine whether or not a WFF is a tautology.
Input
Input consists of several test cases. Each test case is a single line containing a WFF with no more than 100 symbols. A line containing 0 follows the last case.
Output
For each test case, output a line containing tautology or not as appropriate.
Sample Input
ApNp ApNq 0
Sample Output
tautology not 实在是读不懂什么意思,后来找篇博客,才知道什么意思,英语好渣#include <iostream> #include <cstring> #include <cstdio> #include <cmath> #include <string> #include <stack> #include <algorithm> using namespace std; const int Max=1100000; int Arr[6]; int top; string str; stack<int>a; void Bit(int num) { int top=0; memset(Arr,0,sizeof(Arr)); while(num) { Arr[top++]=num%2; num/=2; } } bool Jud(char s) { switch(s) { case 'p':a.push(Arr[0]);break; case 'q':a.push(Arr[1]);break; case 'r':a.push(Arr[2]);break; case 's':a.push(Arr[3]);break; case 't':a.push(Arr[4]);break; default :return 0; } return 1; } void Count(char s) { switch(s) { case 'K': { int x=a.top();a.pop(); int y=a.top();a.pop(); a.push(x&&y); } break; case 'A': { int x=a.top();a.pop(); int y=a.top();a.pop(); a.push(x||y); } break; case 'N': { int x=a.top();a.pop(); a.push(!x); } break; case 'C': { int x=a.top();a.pop(); int y=a.top();a.pop(); a.push((!x)||y); } break; case 'E': { int x=a.top();a.pop(); int y=a.top();a.pop(); a.push(x==y); } break; } } bool Cal() { int len=str.length(); for(int i=0;i<=31;i++) { Bit(i); for(int j=len-1;j>=0;j--) { if(!Jud(str[j])) { Count(str[j]); } } int x=a.top(); a.pop(); if(!x) return false; } return true; } int main() { while(cin>>str) { if(str=="0") break; if(Cal()) { cout<<"tautology"<<endl; } else { cout<<"not"<<endl; } } }
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