• -sql语句练习50题(Mysql学习练习版)


    –1.学生表 
    Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别 
    –2.课程表 
    Course(c_id,c_name,t_id) – –课程编号, 课程名称, 教师编号 
    –3.教师表 
    Teacher(t_id,t_name) –教师编号,教师姓名 
    –4.成绩表 
    Score(s_id,c_id,s_score) –学生编号,课程编号,分数
    
    测试数据
    
    --建表
    --学生表
    CREATE TABLE `Student`(
        `s_id` VARCHAR(20),
        `s_name` VARCHAR(20) NOT NULL DEFAULT '',
        `s_birth` VARCHAR(20) NOT NULL DEFAULT '',
        `s_sex` VARCHAR(10) NOT NULL DEFAULT '',
        PRIMARY KEY(`s_id`)
    );
    --课程表
    CREATE TABLE `Course`(
        `c_id`  VARCHAR(20),
        `c_name` VARCHAR(20) NOT NULL DEFAULT '',
        `t_id` VARCHAR(20) NOT NULL,
        PRIMARY KEY(`c_id`)
    );
    --教师表
    CREATE TABLE `Teacher`(
        `t_id` VARCHAR(20),
        `t_name` VARCHAR(20) NOT NULL DEFAULT '',
        PRIMARY KEY(`t_id`)
    );
    --成绩表
    CREATE TABLE `Score`(
        `s_id` VARCHAR(20),
        `c_id`  VARCHAR(20),
        `s_score` INT(3),
        PRIMARY KEY(`s_id`,`c_id`)
    );
    --插入学生表测试数据
    insert into Student values('01' , '赵雷' , '1990-01-01' , '男');
    insert into Student values('02' , '钱电' , '1990-12-21' , '男');
    insert into Student values('03' , '孙风' , '1990-05-20' , '男');
    insert into Student values('04' , '李云' , '1990-08-06' , '男');
    insert into Student values('05' , '周梅' , '1991-12-01' , '女');
    insert into Student values('06' , '吴兰' , '1992-03-01' , '女');
    insert into Student values('07' , '郑竹' , '1989-07-01' , '女');
    insert into Student values('08' , '王菊' , '1990-01-20' , '女');
    --课程表测试数据
    insert into Course values('01' , '语文' , '02');
    insert into Course values('02' , '数学' , '01');
    insert into Course values('03' , '英语' , '03');
    
    --教师表测试数据
    insert into Teacher values('01' , '张三');
    insert into Teacher values('02' , '李四');
    insert into Teacher values('03' , '王五');
    
    --成绩表测试数据
    insert into Score values('01' , '01' , 80);
    insert into Score values('01' , '02' , 90);
    insert into Score values('01' , '03' , 99);
    insert into Score values('02' , '01' , 70);
    insert into Score values('02' , '02' , 60);
    insert into Score values('02' , '03' , 80);
    insert into Score values('03' , '01' , 80);
    insert into Score values('03' , '02' , 80);
    insert into Score values('03' , '03' , 80);
    insert into Score values('04' , '01' , 50);
    insert into Score values('04' , '02' , 30);
    insert into Score values('04' , '03' , 20);
    insert into Score values('05' , '01' , 76);
    insert into Score values('05' , '02' , 87);
    insert into Score values('06' , '01' , 31);
    insert into Score values('06' , '03' , 34);
    insert into Score values('07' , '02' , 89);
    insert into Score values('07' , '03' , 98);
    
    
    
    
    练习题和sql语句
    
    -- 1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数  
    
    select a.* ,b.s_score as 01_score,c.s_score as 02_score from 
        student a 
        join score b on a.s_id=b.s_id and b.c_id='01'
        left join score c on a.s_id=c.s_id and c.c_id='02' or c.c_id = NULL where b.s_score>c.s_score
    
    
    -- 2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数
    
    select a.* ,b.s_score as 01_score,c.s_score as 02_score from 
        student a left join score b on a.s_id=b.s_id and b.c_id='01' or b.c_id=NULL 
         join score c on a.s_id=c.s_id and c.c_id='02' where b.s_score<c.s_score
    
    
    -- 3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩
    select b.s_id,b.s_name,ROUND(AVG(a.s_score),2) as avg_score from 
        student b 
        join score a on b.s_id = a.s_id
        GROUP BY b.s_id,b.s_name HAVING ROUND(AVG(a.s_score),2)>=60;
    
    
    -- 4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩
            -- (包括有成绩的和无成绩的)
    
    select b.s_id,b.s_name,ROUND(AVG(a.s_score),2) as avg_score from 
        student b 
        left join score a on b.s_id = a.s_id
        GROUP BY b.s_id,b.s_name HAVING ROUND(AVG(a.s_score),2)<60
        union
    select a.s_id,a.s_name,0 as avg_score from 
        student a 
        where a.s_id not in (
                    select distinct s_id from score);
    
    
    -- 5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩
    select a.s_id,a.s_name,count(b.c_id) as sum_course,sum(b.s_score) as sum_score from 
        student a 
        left join score b on a.s_id=b.s_id
        GROUP BY a.s_id,a.s_name;
    
    
    -- 6、查询"李"姓老师的数量 
    select count(t_id) from teacher where t_name like '李%';
    
    -- 7、查询学过"张三"老师授课的同学的信息 
    select a.* from 
        student a 
        join score b on a.s_id=b.s_id where b.c_id in(
            select c_id from course where t_id =(
                select t_id from teacher where t_name = '张三'));
    
    -- 8、查询没学过"张三"老师授课的同学的信息 
    select * from 
        student c 
        where c.s_id not in(
            select a.s_id from student a join score b on a.s_id=b.s_id where b.c_id in(
                select c_id from course where t_id =(
                    select t_id from teacher where t_name = '张三')));
    -- 9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息
    
    select a.* from 
        student a,score b,score c 
        where a.s_id = b.s_id  and a.s_id = c.s_id and b.c_id='01' and c.c_id='02';
    
    -- 10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息
    
    select a.* from 
        student a 
        where a.s_id in (select s_id from score where c_id='01' ) and a.s_id not in(select s_id from score where c_id='02')
    
    
    -- 11、查询没有学全所有课程的同学的信息 
    
    select s.* from 
        student s where s.s_id in(
            select s_id from score where s_id not in(
                select a.s_id from score a 
                    join score b on a.s_id = b.s_id and b.c_id='02'
                    join score c on a.s_id = c.s_id and c.c_id='03'
                where a.c_id='01'))
    
    -- 12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息 
    
    select * from student where s_id in(
        select distinct a.s_id from score a where a.c_id in(select a.c_id from score a where a.s_id='01')
        );
    
    -- 13、查询和"01"号的同学学习的课程完全相同的其他同学的信息 
    
    select a.* from student a where a.s_id in(
        select distinct s_id from score where s_id!='01' and c_id in(select c_id from score where s_id='01')
        group by s_id 
        having count(1)=(select count(1) from score where s_id='01'));
    -- 14、查询没学过"张三"老师讲授的任一门课程的学生姓名 
    select a.s_name from student a where a.s_id not in (
        select s_id from score where c_id = 
                    (select c_id from course where t_id =(
                        select t_id from teacher where t_name = '张三')) 
                    group by s_id);
    
    -- 15、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩 
    select a.s_id,a.s_name,ROUND(AVG(b.s_score)) from 
        student a 
        left join score b on a.s_id = b.s_id
        where a.s_id in(
                select s_id from score where s_score<60 GROUP BY  s_id having count(1)>=2)
        GROUP BY a.s_id,a.s_name
    
    -- 16、检索"01"课程分数小于60,按分数降序排列的学生信息
    select a.*,b.c_id,b.s_score from 
        student a,score b 
        where a.s_id = b.s_id and b.c_id='01' and b.s_score<60 ORDER BY b.s_score DESC;
    
    -- 17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
    select a.s_id,(select s_score from score where s_id=a.s_id and c_id='01') as 语文,
                    (select s_score from score where s_id=a.s_id and c_id='02') as 数学,
                    (select s_score from score where s_id=a.s_id and c_id='03') as 英语,
                round(avg(s_score),2) as 平均分 from score a  GROUP BY a.s_id ORDER BY 平均分 DESC;
    
    -- 18.查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率
    --及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90
    select a.c_id,b.c_name,MAX(s_score),MIN(s_score),ROUND(AVG(s_score),2),
        ROUND(100*(SUM(case when a.s_score>=60 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 及格率,
        ROUND(100*(SUM(case when a.s_score>=70 and a.s_score<=80 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 中等率,
        ROUND(100*(SUM(case when a.s_score>=80 and a.s_score<=90 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 优良率,
        ROUND(100*(SUM(case when a.s_score>=90 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 优秀率
        from score a left join course b on a.c_id = b.c_id GROUP BY a.c_id,b.c_name
    
    -- 19、按各科成绩进行排序,并显示排名(实现不完全)
    -- mysql没有rank函数
        select a.s_id,a.c_id,
            @i:=@i +1 as i保留排名,
            @k:=(case when @score=a.s_score then @k else @i end) as rank不保留排名,
            @score:=a.s_score as score
        from (
            select s_id,c_id,s_score from score WHERE c_id='01' GROUP BY s_id,c_id,s_score ORDER BY s_score DESC
    )a,(select @k:=0,@i:=0,@score:=0)s
        union
        select a.s_id,a.c_id,
            @i:=@i +1 as i,
            @k:=(case when @score=a.s_score then @k else @i end) as rank,
            @score:=a.s_score as score
        from (
            select s_id,c_id,s_score from score WHERE c_id='02' GROUP BY s_id,c_id,s_score ORDER BY s_score DESC
    )a,(select @k:=0,@i:=0,@score:=0)s
        union
        select a.s_id,a.c_id,
            @i:=@i +1 as i,
            @k:=(case when @score=a.s_score then @k else @i end) as rank,
            @score:=a.s_score as score
        from (
            select s_id,c_id,s_score from score WHERE c_id='03' GROUP BY s_id,c_id,s_score ORDER BY s_score DESC
    )a,(select @k:=0,@i:=0,@score:=0)s
    
    -- 20、查询学生的总成绩并进行排名
    select a.s_id,
        @i:=@i+1 as i,
        @k:=(case when @score=a.sum_score then @k else @i end) as rank,
        @score:=a.sum_score as score
    from (select s_id,SUM(s_score) as sum_score from score GROUP BY s_id ORDER BY sum_score DESC)a,
        (select @k:=0,@i:=0,@score:=0)s
    
    -- 21、查询不同老师所教不同课程平均分从高到低显示 
    
        select a.t_id,c.t_name,a.c_id,ROUND(avg(s_score),2) as avg_score from course a
            left join score b on a.c_id=b.c_id 
            left join teacher c on a.t_id=c.t_id
            GROUP BY a.c_id,a.t_id,c.t_name ORDER BY avg_score DESC;
    -- 22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩
    
                select d.*,c.排名,c.s_score,c.c_id from (
                    select a.s_id,a.s_score,a.c_id,@i:=@i+1 as 排名 from score a,(select @i:=0)s where a.c_id='01'    
                )c
                left join student d on c.s_id=d.s_id
                where 排名 BETWEEN 2 AND 3
                UNION
                select d.*,c.排名,c.s_score,c.c_id from (
                    select a.s_id,a.s_score,a.c_id,@j:=@j+1 as 排名 from score a,(select @j:=0)s where a.c_id='02'    
                )c
                left join student d on c.s_id=d.s_id
                where 排名 BETWEEN 2 AND 3
                UNION
                select d.*,c.排名,c.s_score,c.c_id from (
                    select a.s_id,a.s_score,a.c_id,@k:=@k+1 as 排名 from score a,(select @k:=0)s where a.c_id='03'    
                )c
                left join student d on c.s_id=d.s_id
                where 排名 BETWEEN 2 AND 3;
    
    
    -- 23、统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比
    
    
            select distinct f.c_name,a.c_id,b.`85-100`,b.百分比,c.`70-85`,c.百分比,d.`60-70`,d.百分比,e.`0-60`,e.百分比 from score a
                    left join (select c_id,SUM(case when s_score >85 and s_score <=100 then 1 else 0 end) as `85-100`,
                                                ROUND(100*(SUM(case when s_score >85 and s_score <=100 then 1 else 0 end)/count(*)),2) as 百分比
                                    from score GROUP BY c_id)b on a.c_id=b.c_id
                    left join (select c_id,SUM(case when s_score >70 and s_score <=85 then 1 else 0 end) as `70-85`,
                                                ROUND(100*(SUM(case when s_score >70 and s_score <=85 then 1 else 0 end)/count(*)),2) as 百分比
                                    from score GROUP BY c_id)c on a.c_id=c.c_id
                    left join (select c_id,SUM(case when s_score >60 and s_score <=70 then 1 else 0 end) as `60-70`,
                                                ROUND(100*(SUM(case when s_score >60 and s_score <=70 then 1 else 0 end)/count(*)),2) as 百分比
                                    from score GROUP BY c_id)d on a.c_id=d.c_id
                    left join (select c_id,SUM(case when s_score >=0 and s_score <=60 then 1 else 0 end) as `0-60`,
                                                ROUND(100*(SUM(case when s_score >=0 and s_score <=60 then 1 else 0 end)/count(*)),2) as 百分比
                                    from score GROUP BY c_id)e on a.c_id=e.c_id
                    left join course f on a.c_id = f.c_id
            ---也可以这么做
              SELECT 
    	    c.c_id,
    	    c.c_name,
    	    a.`85-100`,
    	    a.`85-100百分比`,
    	    b.`70-85`,
    	    b.`70-85百分比`,
    	    ce.`60-70`,
    	    ce.`60-70百分比`,
    	    d.`0-60`,
    	    d.`0-60百分比`
            FROM course c
            LEFT JOIN(SELECT s.c_id,SUM(CASE WHEN s.s_score >85 AND s.s_score <= 100 THEN 1 ELSE 0 END) AS "85-100",ROUND(100*SUM(CASE WHEN s.s_score >85 AND s.s_score <= 100 THEN 1 ELSE 0 END)/count(1),2) as "85-100百分比" FROM score s                 GROUP BY s.c_id) a ON a.c_id = c.c_id
            LEFT JOIN(SELECT s.c_id,SUM(CASE WHEN s.s_score >85 AND s.s_score <= 100 THEN 1 ELSE 0 END) AS "70-85",ROUND(100*SUM(CASE WHEN s.s_score >70 AND s.s_score <= 85 THEN 1 ELSE 0 END)/count(1),2) as "70-85百分比" FROM score s GROUP BY s.c_id) b ON b.c_id = c.c_id
            LEFT JOIN(SELECT s.c_id,SUM(CASE WHEN s.s_score >85 AND s.s_score <= 100 THEN 1 ELSE 0 END) AS "60-70",ROUND(100*SUM(CASE WHEN s.s_score >60 AND s.s_score <= 70 THEN 1 ELSE 0 END)/count(1),2) as "60-70百分比" FROM score s GROUP BY s.c_id) ce ON ce.c_id = c.c_id
            LEFT JOIN(SELECT s.c_id,SUM(CASE WHEN s.s_score >85 AND s.s_score <= 100 THEN 1 ELSE 0 END) AS "0-60",ROUND(100*SUM(CASE WHEN s.s_score >0 AND s.s_score <= 60 THEN 1 ELSE 0 END)/count(1),2) as "0-60百分比" FROM score s GROUP BY s.c_id) d ON d.c_id = c.c_id
    
    -- 24、查询学生平均成绩及其名次 
    
            select a.s_id,
                    @i:=@i+1 as '不保留空缺排名',
                    @k:=(case when @avg_score=a.avg_s then @k else @i end) as '保留空缺排名',
                    @avg_score:=avg_s as '平均分'
            from (select s_id,ROUND(AVG(s_score),2) as avg_s from score GROUP BY s_id)a,(select @avg_score:=0,@i:=0,@k:=0)b;
    -- 25、查询各科成绩前三名的记录
                -- 1.选出b表比a表成绩大的所有组
                -- 2.选出比当前id成绩大的 小于三个的
            select a.s_id,a.c_id,a.s_score from score a 
                left join score b on a.c_id = b.c_id and a.s_score<b.s_score
                group by a.s_id,a.c_id,a.s_score HAVING COUNT(b.s_id)<3
                ORDER BY a.c_id,a.s_score DESC
    
    -- 26、查询每门课程被选修的学生数 
    
            select c_id,count(s_id) from score a GROUP BY c_id
    
    -- 27、查询出只有两门课程的全部学生的学号和姓名 
            select s_id,s_name from student where s_id in(
                    select s_id from score GROUP BY s_id HAVING COUNT(c_id)=2);
            ---另外一种写法
                    SELECT 
    	            st.s_id,
    	            st.s_name
                    FROM student st
                    INNER JOIN(
                        SELECT 
    	                s.s_id
                        FROM score s
                        GROUP BY s_id
                        HAVING COUNT(s.c_id) = 2
                    ) a ON a.s_id = st.s_id;
    
    -- 28、查询男生、女生人数 
            select s_sex,COUNT(s_sex) as 人数  from student GROUP BY s_sex
    
    -- 29、查询名字中含有"风"字的学生信息
    
            select * from student where s_name like '%风%';
    
    -- 30、查询同名同性学生名单,并统计同名人数 
    
            select a.s_name,a.s_sex,count(*) from student a  JOIN 
                        student b on a.s_id !=b.s_id and a.s_name = b.s_name and a.s_sex = b.s_sex
            GROUP BY a.s_name,a.s_sex
    
    
    
    -- 31、查询1990年出生的学生名单
    
            select s_name from student where s_birth like '1990%'
    
    -- 32、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列 
    
        select c_id,ROUND(AVG(s_score),2) as avg_score from score GROUP BY c_id ORDER BY avg_score DESC,c_id ASC
    
    -- 33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩 
    
        select a.s_id,b.s_name,ROUND(avg(a.s_score),2) as avg_score from score a
            left join student b on a.s_id=b.s_id GROUP BY s_id HAVING avg_score>=85
    
    -- 34、查询课程名称为"数学",且分数低于60的学生姓名和分数 
    
            select a.s_name,b.s_score from score b LEFT JOIN student a on a.s_id=b.s_id where b.c_id=(
                        select c_id from course where c_name ='数学') and b.s_score<60
    
            ----另外一种自己的写法
            SELECT
                st.s_name,
                s.s_score
            FROM student st
            INNER JOIN score s ON s.s_id = st.s_id
            INNER JOIN course c ON c.c_id = s.c_id AND c.c_name = '数学'
            WHERE s.s_score < 60;
    
    -- 35、查询所有学生的课程及分数情况; 
    
    
            select a.s_id,a.s_name,
                        SUM(case c.c_name when '语文' then b.s_score else 0 end) as '语文',
                        SUM(case c.c_name when '数学' then b.s_score else 0 end) as '数学',
                        SUM(case c.c_name when '英语' then b.s_score else 0 end) as '英语',
                        SUM(b.s_score) as  '总分'
            from student a left join score b on a.s_id = b.s_id 
            left join course c on b.c_id = c.c_id 
            GROUP BY a.s_id,a.s_name
            --注意case when...和case...when的用法
    
    
     -- 36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数; 
                select a.s_name,b.c_name,c.s_score from course b left join score c on b.c_id = c.c_id
                    left join student a on a.s_id=c.s_id where c.s_score>=70
    
            ----另外一种过滤方法
                SELECT
    	        st.s_name,
    	        c.c_name,
    	        s.s_score
                FROM course c
                LEFT JOIN score s on s.c_id = c.c_id AND s.s_score > 70
                LEFT JOIN student st ON st.s_id = s.s_id
    
    -- 37、查询不及格的课程
            select a.s_id,a.c_id,b.c_name,a.s_score from score a left join course b on a.c_id = b.c_id
                where a.s_score<60 
    
    --38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名; 
            select a.s_id,b.s_name from score a LEFT JOIN student b on a.s_id = b.s_id
                where a.c_id = '01' and a.s_score>80
    
    -- 39、求每门课程的学生人数 
            select count(*) from score GROUP BY c_id;
    
    -- 40、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩
    
    
            -- 查询老师id   
            select c_id from course c,teacher d where c.t_id=d.t_id and d.t_name='张三'
            -- 查询最高分(可能有相同分数)
            select MAX(s_score) from score where c_id='02'
            -- 查询信息
            select a.*,b.s_score,b.c_id,c.c_name from student a
                LEFT JOIN score b on a.s_id = b.s_id
                LEFT JOIN course c on b.c_id=c.c_id
                where b.c_id =(select c_id from course c,teacher d where c.t_id=d.t_id and d.t_name='张三')
                and b.s_score in (select MAX(s_score) from score where c_id='02')
            --可以将上面组织一下,一次查询出来如下:
                SELECT
    	        st.*
                FROM student st 
                left JOIN score s on s.s_id = st.s_id
                left JOIN course c on c.c_id = s.c_id
                WHERE s.c_id = (SELECT c_id FROM course c,teacher t WHERE c.t_id = t.t_id AND t.t_name LIKE '张三') 
                AND s.s_score in (SELECT max(s_score) FROM score WHERE c_id = (SELECT c_id FROM course c,teacher t WHERE c.t_id = t.t_id AND t.t_name LIKE '张三'))
    
    
    -- 41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩 
        select DISTINCT b.s_id,b.c_id,b.s_score from score a,score b where a.c_id != b.c_id and a.s_score = b.s_score
    
    
    -- 42、查询每门功成绩最好的前两名 
            -- 牛逼的写法
        select a.s_id,a.c_id,a.s_score from score a
            where (select COUNT(1) from score b where b.c_id=a.c_id and b.s_score>=a.s_score)<=2 ORDER BY a.c_id
    
    
    -- 43、统计每门课程的学生选修人数(超过5人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列  
            select c_id,count(*) as total from score GROUP BY c_id HAVING total>5 ORDER BY total,c_id ASC
    
    -- 44、检索至少选修两门课程的学生学号 
            select s_id,count(*) as sel from score GROUP BY s_id HAVING sel>=2
    
    -- 45、查询选修了全部课程的学生信息 
            select * from student where s_id in(        
                select s_id from score GROUP BY s_id HAVING count(*)=(select count(*) from course))
    
    
    --46、查询各学生的年龄
        -- 按照出生日期来算,当前月日 < 出生年月的月日则,年龄减一
    
        select s_birth,(DATE_FORMAT(NOW(),'%Y')-DATE_FORMAT(s_birth,'%Y') - 
                    (case when DATE_FORMAT(NOW(),'%m%d')>DATE_FORMAT(s_birth,'%m%d') then 0 else 1 end)) as age
            from student;
    
    
    -- 47、查询本周过生日的学生
        select * from student where WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))=WEEK(s_birth)
        select * from student where YEARWEEK(s_birth)=YEARWEEK(DATE_FORMAT(NOW(),'%Y%m%d'))
    
        select WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))
    
    -- 48、查询下周过生日的学生
        select * from student where WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))+1 =WEEK(s_birth)
    
    -- 49、查询本月过生日的学生
    
        select * from student where MONTH(DATE_FORMAT(NOW(),'%Y%m%d')) =MONTH(s_birth)
    
    -- 50、查询下月过生日的学生
        select * from student where MONTH(DATE_FORMAT(NOW(),'%Y%m%d'))+1 =MONTH(s_birth)
    
    
  • 相关阅读:
    关于JSON可能出现的错误,待更/todo
    mongoose的安装与使用(书签记录) 2017
    HTTP的学习记录3--HTTPS和HTTP
    HTTP的学习记录(二)头部
    HTTP(一)概述
    LeetCode 455. Assign Cookies
    LeetCode 453. Minimum Moves to Equal Array Elements
    LeetCode 448. Find All Numbers Disappeared in an Array
    LeetCode 447. Number of Boomerangs
    LeetCode 416. Partition Equal Subset Sum
  • 原文地址:https://www.cnblogs.com/jpfss/p/9138882.html
Copyright © 2020-2023  润新知